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madreJ [45]
3 years ago
9

Convert 0.7 to a fraction in simplified form

Mathematics
1 answer:
Trava [24]3 years ago
4 0
0.7 = 7/10

One digit after the decimal point is the tens place

0.7 also equals 70/100, which can be simplified to 7/10, but 7/10 cannot be simplified
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Mrs. Daly's reading classes were surveyed about their reading preferences. The data is summarized in the table below.
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Count the total number of students who prefer fiction novels: In 9th grade there are 35, in 10th grade there are 52, so there are 87 students who prefer fictions. The proportion of 10th grade students out of these 87 students is 52/87=0.60 approximately.
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Read 2 more answers
Fill in the blank.
Marrrta [24]

Question:

Fill in the blank.

23 x 6 = (20 + 3) * 6

23 x 6 = _ + (3x6)

Options

20 * 6

20 * 3

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Answer:

20 * 6

Step-by-step explanation:

Given

Expression 1:  23 * 6 = (20 + 3) * 6

Expression 2:  23 * 6 = __ + (3 * 6)

Required

Fill in the blank

From Expression 1

23 * 6 = (20 + 3)*6

Using Distributive Property; The expression becomes

23 * 6 = 20 * 6 + 3 * 6

23 * 6 = (20 * 6) + (3 * 6)

By Comparing this with expression 2

23 * 6 = __ + (3 * 6)

The blank position is occupied by 20 * 6.

Hence, the correct option that fills the missing blank correctly is 20 * 6

7 0
2 years ago
Determine whether the following lines represented by the vector equations below intersect, are parallel, are skew, or are identi
KiRa [710]

Answer:

r(t) and s(t) are parallel.

Step-by-step explanation:

Given that :

the  lines represented by the vector equations are:

r(t)=⟨1−t,3+2t,−3t⟩

s(t)=⟨2t,−3−4t,3+6t⟩

The objective is to determine if the following lines represented by the vector equations below intersect, are parallel, are skew, or are identical.

NOTE:

Two lines will be parallel if \dfrac{x_1}{x_2}= \dfrac{y_1}{y_2}= \dfrac{z_1}{z_2}

here;

d_1 = (-1, \ 2, \ -3)

Thus;

r(t) = \dfrac{x-1}{-1} = \dfrac{y-3}{2}=\dfrac{z-0}{-3} = t

d_2 =(2, \ -4, \  +6)

s(t) = \dfrac{x-0}{2} = \dfrac{y+5}{-4}=\dfrac{z-3}{6} = t

∴

\dfrac{d_1}{d_2}= \dfrac{-1}{2} = \dfrac{2}{-4}= \dfrac{-3}{-6}

Hence, we can conclude that r(t) and s(t) are parallel.

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