The banking angle of the curved part of the speedway is determined as 32⁰.
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Banking angle of the curved road</h3>
The banking angle of the curved part of the speedway is calculated as follows;
V(max) = √(rg tanθ)
where;
- r is radius of the path
- g is acceleration due to gravity
V² = rg tanθ
tanθ = V²/rg
tanθ = (34²)/(190 x 9.8)
tanθ = 0.62
θ = arc tan(0.62)
θ = 31.8
θ ≈ 32⁰
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The answer is a mood disorder
Current = (voltage) / (resistance)
= (35 volts) / (1,400 ohms)
= 25 milliamperes
I think the answer might be b