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3 years ago

Why was the idea of continental drift not initially accepted by many other scientists and the general public at the time?

1 answer:

4 0

Because the idea that the ground that we live, stand, and build on is actually moving beneath us blew the minds of scientists.

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Uma partícula com carga “Q”, no vácuo, gera um potencial elétrico de 600 volts a uma distância de 6,0 m, determine o valor dessa

garik1379 [7]

Answer:

q = 400 nC

the correct answer is b

Explanation:

The expression for the electric potential of a point charge is

V = k q / r

they ask us for the electrical charge

q = V r / k

let's calculate

Q = 600 6.0 / 9 10⁹

Q = 4 10⁻⁷ C

let's reduce to nC

Q = 4 10⁻⁷ C (10⁹ nC / 1C)

q = 4 10² nC = 400 nC

the correct answer is b

Traslate

La expresión para el potencial eléctrico de una carga puntual es

V = k q/r

nos piden la carga eléctrica

q= V r /k

calculemos

Q= 600 6,0 / 9 10⁹

Q= 4 10⁻⁷ C

reduzcamos a nC

Q = 4 10⁻⁷ C(10⁹ nC/1C )

q = 4 10² nC = 400 nC

la respuesta correcta es b

8 0

3 years ago

For a particular casting setup, the top of the sprue has a diameter of 0.030 m, and its length is 0.200 m. The volume flow rate

faust18 [17]

Answer with Explanation:

We are given that

Diameter=0.030 m

Length of sprue= $h_1$ =0.200 m

Metal volume flow rate,Q=0.03 $m^3/min$

Q= $\frac{0.03}{60}=5\times 10^{-4}m^3/s$ because 1 minute=60 seconds

Let 1 for the top and 2 for the bottom

$d_=0.030 m$

$h_2=0$

$A_1=\frac{\pi d^2}{4}=\frac{3.14\times (0.030)^2}{4}$

$A_1=7.065\times 10^{-4} m^2$

$v_1=\frac{Q}{A_1}=\frac{5\times 10^{-4}}{7.065\times 10^{-4}}$

$v_1=0.708 m/s$

Pressure at the top and bottom of the sprue is atmospheric

$h_1+\frac{v^2_1}{2g}=h_2+\frac{v^2_2}{2g}$

Substitute the values

$0.2+\frac{(0.708)^2}{2\cdot 9.8}=0+\frac[v^2_2}{2\cdot 9.8}$

$v^2_2=2\cdot 9.8\cdot \frac{0.2\cdot 9.8\cdot 2+0.501264}{2\cdot 9.8}=4.421264$

$v_2=\sqrt{4.421264}=2.1 m/s$

$Q=A_2v_2$

$5\times 10^{-4}=A_2\times 2.1$

$A_2=\frac{5\times 10^{-4}}{2.1}=2.381\times 10^{-4} m^2$

Reynolds number= $\frac{v_2D\rho}{\eta}$

$\eta=0.004 N.s/m^2$

$\rho=2700 kg/m^3$

Substitute the values then we get

Reynolds number= $\frac{2.1\times 0.03\times 2700}{0.004}$

Reynolds number=42525

The Reynolds number is greater than 4000 .Therefore, the flow is turbulent.

8 0

3 years ago

At what position in its elliptical orbit is the speed of a planet a maximum? when it is closest to the sun when it is farthest f

Phantasy [73]

Answer:

1.when it is closest to the sun

2.when it is midway between its farthest

Explanation:

According to the law of Kepler's

T ² ∝ r³

T=Time period

r=semi major axis

We also know that time period T given as

$T=\dfrac{2\pi r}{v}$

v=Speed

$v=\dfrac{2\pi r}{T}$

$v\alpha \dfrac{r}{T}$

$v^2\alpha \dfrac{r^2}{T^2}$

$v^2\alpha \dfrac{r^2}{r^3}$

$v^2\alpha \dfrac{1}{r}$

$v\alpha \dfrac{1}{\sqrt{r}}$

So we can say that ,when r is more then the speed will be minimum and when r is low then speed will be maximum.

7 0

3 years ago

A _______ contains several blades of differing thicknesses and is used to measure the clearance between parts. A. dial in

Likurg_2 [28]

This is D. Feeler Gage

5 0

3 years ago

Mass is 56.8 g and the volume is 10 mL what is the density

scoundrel [369]

Answer: 5.68g/ML.

Explanation; Divide the mass of the unknown substance and the volume of the unknown substance and you will have your answer.

Hope this helps! ^^ if you can pls mark me brainiest!

6 0

3 years ago