Question

1. How many milliliters of a 0.184 M NaNO3 solution contain 0.113 moles of NaNO3?ans:614 mL

Answer 1

C=0.184 mol/L
n=0.113 mol

n=CV

V=n/C

V=0.113/0.184=0.614 L = 614 mL

Answer 2

Explanation:

The given data is as follows.

        Molarity of solution = 0.184 M

        Volume of solution = ?

         number of moles = 0.113 mol

As molarity is the number of moles present in liter of solvent.

Mathematically,      Molarity = $\frac{\text{No. of moles}}{\text{Volume}}$

Hence, calculate the volume of given solution as follows.

                  Molarity = $\frac{\text{No. of moles}}{\text{Volume}}$

                  0.184 M = $\frac{0.113 mol}{volume}$

                     volume = 0.614 L

As 1 L = 1000 mililiter. Hence convert 0.614 L into ml as follows.

                      $0.614 L \times \frac{1000 ml}{1 L}$

                       = 614 ml

Thus, we can conclude that the volume of given solution is 614 ml.