0.29 M ammonia + 0.38 M ammonium bromide and 0.22 M hypochlorous acid + 0.18 M hydroiodic acids of aqueous solutions are good buffer systems.
<h3>Buffer Systems:</h3>
A solution that resists pH change when acids or bases are added to it is referred to as a buffer system. Either a weak acid and its salt, or a weak base and its salt, make up buffer systems. The ratio of HX/X- does not considerably alter when an acid or a base is introduced to a buffer.
Solutions known as buffers withstand pH changes when an acid or base is added. A weak base (A) and its conjugate weak acid (HA) are both present in buffers. When a reactive system is in equilibrium, adding a strong electrolyte with one common ion will cause the equilibrium to shift, lowering the concentration of the common ion. Buffers differ from one another in terms of pH range and buffer capacity.
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Answer:
0.31 mol K x 39.1 grams K/ 1 mol k = 12.1 g
Explanation:
molar mass of K: 39.1
In order to find the mass in 0.31 mol of K, you must covert moles to grams. In one mole of Potassium there is 39.1 grams.
Answer:
The density of Ammonia : 6.25.10⁻⁴ g/cm³
Further explanation
Density is a quantity derived from the mass and volume
Density is the ratio of mass per unit volume
With the same mass, the volume of objects that have a high density will be smaller than objects with a smaller density
The unit of density can be expressed in g/cm³ or kg/m³
Density formula:
\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}ρ = Vm
ρ = density
m = mass
v = volume
A common example is the water density of 1 gr/cm³
Ammonia has a density of 0.625 g/L, then convert to g/cm³ :
\begin{gathered}\rm 1~L=1~dm^3=10^3~cm^3\\\\0.625~\dfrac{g}{L}\times \dfrac{1~L}{10^3~cm^3}\\\\\rho=\dfrac{0.625}{10^3}}\dfrac{g}{cm^3}=\boxed{6.25.10^{-4}\dfrac{g}{cm^3}}\end{gathered}
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Answer:
dark coloured rock with coarse grains in parallel layers
Explanation:
