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Marianna [84]
3 years ago
6

Calculate the number of moles in a 14.5 gram sample of C4H10.

Chemistry
1 answer:
cricket20 [7]3 years ago
6 0
Moles= mass divided by molar mass
Molar mass= 12.01(4) + 1.01(10)
                 = 58.14g/mol

Moles=14.5g / 58.14g/mol
         =0.249

Therefore there are approx 0.249 moles in a 14.5g sample of C4H10
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Answer:

P_{N_2}=1.0atm

Explanation:

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Considering the Dalton's law which states that the total pressure of a gaseous system is defined by the summation of the the partial pressures of the present gases:

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For the given system:

P_T=P_{H_2}+P_{N_2}+P_{CH_4}

Solving for the partial pressure of nitrogen we obtain:

P_{N_2}=3.0atm-0.5atm-1.5atm=1.0atm

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Acetaldehyde decomposes at 750 K: CH3CHO → CO + CH4. The reaction is first order in acetaldehyde and the half-life of the reacti
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A solution contains 15.27 grams of NaCl in 0.670 kg water at 25 °C. What is the vapor pressure of the solution?
Anvisha [2.4K]

Answer:

The vapor pressure of the solution is 23.636 torr

Explanation:

P_{solution} = X_{solvent}*P_{solvent}

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P_{solution is the vapor pressure of the solution

X_{solvent is the mole fraction of the solvent

P_{solvent is the vapor pressure of the pure solvent

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15.27 g of NaCl = [(15.27)/(58.5)]moles = 0.261 moles of NaCl

0.67 kg of water =  [(0.67*1000)/(18)]moles = 37.222 moles of H₂O

Mole fraction of solvent (water) = (number of moles of water)/(total number of moles present in solution)

Mole fraction of solvent (water) = (37.222)/(37.222+0.261)

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Therefore, the vapor pressure of the solution = 0.993 * 0.0313 atm

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5 0
3 years ago
Read 2 more answers
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