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Leya [2.2K]
3 years ago
5

A cell is put into a liquid and remains its original size. What is the best conclusion that can be drawn from this observation?

The concentration of water is higher in the cell than in the liquid, so water is leaving the cell. The concentration of water is higher in the cell than in the liquid, so water is moving in and out of the cell at the same rate. The concentration of water in the cell is the same as in the liquid, so water is moving in and out of the cell at the same rate. The concentration of water in the cell is the same as in the liquid, so water is leaving the cell.
Chemistry
2 answers:
irga5000 [103]3 years ago
8 0

Answer:

The concentration of water in the cell is the same as in the liquid, so water is moving in and out of the cell at the same rate.

Explanation:

The cell is essentially placed in an isotonic solution. In an isotonic solution the concentration of water inside the cell is the same as the outside, causing no water to flow in and out of the cell and keeping the size of the cell intact. In a hypertonic solution the concentration of water inside the cell is higher than the outside, causing water to flow out of the cell and shrinking the cell. In a hypotonic solution the concentration of water inside the cell is lower than the outside, causing water to flow in of the cell and making the cell turgid.  

alukav5142 [94]3 years ago
3 0
Hello!

Since the cell remains its original size, it stands to reason that the concentration between the cell and the liquid is the same.

Answer:
<span>The concentration of water in the cell is the same as in the liquid, so water is moving in and out of the cell at the same rate</span>
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Answer:

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Explanation:

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\psi = \sqrt \frac{2}{L} sin(\frac{n \pi x}{L})

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P = \int_{x_{1}}^{x_{2}} \psi^{2} dx

P = \int_{x_{1}}^{x_{2}} (\sqrt \frac{2}{L} sin(\frac{n \pi x}{L}))^{2} dx

P = \frac{2}{L} \int_{x_{1}}^{x_{2}} (sin^{2}(\frac{n \pi x}{L}) dx

Evaluating the above integral from x₁ = 0 to x₂ = L/8 and solving it, we have:

P = \frac{2}{L} [\frac{L}{16} (1 - 4\frac{sin(\frac{n \pi}{4})}{n \pi})]

P = \frac{1}{8} (1 - 4\frac{sin(\frac{n \pi}{4})}{n \pi})    

Solving for n=4:

P = \frac{1}{8} (1 - 4\frac{sin(\frac{4 \pi}{4})}{4 \pi})    

P = \frac{1}{8} (1 - \frac{sin (\pi)}{\pi})    

P = \frac{1}{8}

I hope it helps you!

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More on Charle's law can be found here: brainly.com/question/16927784

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