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Leya [2.2K]
3 years ago
5

A cell is put into a liquid and remains its original size. What is the best conclusion that can be drawn from this observation?

The concentration of water is higher in the cell than in the liquid, so water is leaving the cell. The concentration of water is higher in the cell than in the liquid, so water is moving in and out of the cell at the same rate. The concentration of water in the cell is the same as in the liquid, so water is moving in and out of the cell at the same rate. The concentration of water in the cell is the same as in the liquid, so water is leaving the cell.
Chemistry
2 answers:
irga5000 [103]3 years ago
8 0

Answer:

The concentration of water in the cell is the same as in the liquid, so water is moving in and out of the cell at the same rate.

Explanation:

The cell is essentially placed in an isotonic solution. In an isotonic solution the concentration of water inside the cell is the same as the outside, causing no water to flow in and out of the cell and keeping the size of the cell intact. In a hypertonic solution the concentration of water inside the cell is higher than the outside, causing water to flow out of the cell and shrinking the cell. In a hypotonic solution the concentration of water inside the cell is lower than the outside, causing water to flow in of the cell and making the cell turgid.  

alukav5142 [94]3 years ago
3 0
Hello!

Since the cell remains its original size, it stands to reason that the concentration between the cell and the liquid is the same.

Answer:
<span>The concentration of water in the cell is the same as in the liquid, so water is moving in and out of the cell at the same rate</span>
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Determine the location of the lost significant place value by placing a bar over the digit.

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A simple machine produces 25 joules of output work for every 50 joules of input work . What is the efficiency of this machine ?
nataly862011 [7]
2:1, output is half the input
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When 0.513 g of biphenyl (c12h10 undergoes combustion in a bomb calorimeter, the temperature rises from 26.3 ?c to 29.7 ?c?
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When 0.514 g of biphenyl (C12H10) undergoes combustion in a bomb calorimeter, the temperature rises from 25.8 C to 29.4 C. Find ⌂E rxn for the combustion of biphenyl in kJ/mol biphenyl. The heat capacity of the bomb calorimeter, determined in a separate experiment, is 5.86 kJ/ C. 



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4 years ago
If you have 12.5g of fluoride and 16.2g of sodium, which is the limiting reactant and how sodium fluoride in grams is your theor
Korvikt [17]

Answer:

F2 is the limiting reactant

27.6 grams of NaF is produced.

Explanation:

Balance the equation first.

2Na+ F2 ---> 2NaF

To find the limiting reactant, solve for how much NaF can be produced with Na and F2

12.5g F2 x (1 mole F2/ 38.00 grams F2)x (2 mole NaF/ 1 mole F2)

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16.2g Na x (1 mole Na/ 22.99 grams Na)x (2 mole NaF/ 2 mole Na)

=0.705 moles NaF

Since F2 produced the least NaF, F2 is the limiting reactant.

Now, to find how much NaF there is, use the moles solved above with F2 as the limiting reactant.

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8 0
3 years ago
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Radda [10]

Answer:

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Explanation:

Given:

q = –8 kJ [Heat removed]

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Computation:

Change in internal energy (ΔU) = q + w

Change in internal energy (ΔU) = -8 KJ + (-1 KJ)

Change in internal energy (ΔU) = -8 KJ - 1 KJ

Change in internal energy (ΔU) = -9 KJ

6 0
3 years ago
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