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zavuch27 [327]
3 years ago
9

How many moles of h2so4 will be produced from 8.21 moles of fes2?

Chemistry
2 answers:
ololo11 [35]3 years ago
8 0

Answer:

16.4 mol

Explanation:

H₂SO₄ can be produced from FeS₂ in 3 steps:

Step 1: 4 FeS₂ + 11 O₂ → 2 Fe₂O₃ + 8 SO₂

Step 2: 2 SO₂ + O₂ → 2 SO₃

Step 3: SO₃ + H₂O → H₂SO₄

We can establish the following relations:

  • According to Step 1, the molar ratio of FeS₂ to SO₂ is 4:8.
  • According to Step 2, the molar ratio of SO₂ to SO₃ is 2:2.
  • According to Step 3, the molar ratio of SO₃ to H₂SO₄ is 1:1.

The moles of H₂SO₄ produced from 8.21 moles of FeS₂ are:

8.21molFeS_{2}.\frac{8molSO_{2}}{4molFeS_{2}} .\frac{2molSO_{3}}{2molSO_{2}} .\frac{1molH_{2}SO_{4}}{1molSO_{3}} =16.4molH_{2}SO_{4}

Ierofanga [76]3 years ago
7 0
Well, if the coefficients are both 1, then you will make 8.21 moles.

See the equation is:

x moles= (8.21mol FeS₂)×(1 mole H₂SO₄ ÷ 1 mole FeS₂) = 8.21 moles H₂SO₄

So if you change the coefficients of the equation, your product will be a different number.

Example:
x moles= (8.21mol FeS₂)×(2 mole H₂SO₄ ÷ 1 mole FeS₂) = 16.4 moles H₂SO₄

I hope this helps you out!
Brady

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mariarad [96]

Answer:

4, 16,

Explanation:

SI2 is sulphur diiodide. Sulphur is in group sixteen (six valence electrons) while iodine is in group 17(seven valence electrons).

Since there are two iodine atoms and one sulphur atom, the molecule has twenty valence electrons. Out of these twenty valence electrons, only four are bonding electrons. The other sixteen electrons include the four nonbonding electrons found on sulphur and the twelve non bonding electrons found on the two iodine atoms having six nonbonding electrons each.

7 0
3 years ago
How many grams of HNO3 are produced when 60.0 g of NO2 completely reacts?
olganol [36]
<h3>Answer:</h3>

54.756 g

<h3>Explanation:</h3>

Assuming the equation for the reaction in question;

3NO₂(g) + H₂O(l) → 2HNO₃(aq) + NO(g)

We are given;

  • Mass of NO₂ as 60.0 g

We are required to calculate the mass of HNO₃ produced

  • We can calculate the mass of HNO₃ produced using the following simple steps;
<h3>Step 1: Calculate the moles of NO₂</h3>

Moles = Mass ÷ Molar mass

Molar mass of NO₂ = 46.01 g/mol

Therefore;

Moles of NO₂ = 60.0 g ÷ 46.01 g/mol

                       = 1.304 moles

<h3>Step 2: Calculate the moles of HNO₃ produced </h3>

From the equation, 3 moles of NO₂ reacted to produce 2 mole of HNO₃

Therefore, the mole ratio of NO₂ to HNO₃ is 3 : 2

Thus;

Moles of HNO₃ = Moles of NO₂ × 2/3

                          = 1.304 moles × 2/3

                          = 0.869 Moles

<h3>Step 3: Calculate the mass of HNO₃</h3>

Mass = Moles × Molar mass

Molar mass of HNO₃ = 63.01 g/mol

Therefore;

Mass = 0.869 moles × 63.01 g/mol

         = 54.756 g

Thus, the mass of HNO₃ produced is 54.756 g

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Learn more about Equilibrium

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