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3 years ago

Match each type of consequence with its resulting behavior change

Physics

1 answer:

ira [324]3 years ago

5 0

Answer:

Janet stops parking in handicapped spaces after she gets a big parking ticket. - Positive Punishment

Peter’s recess is taken away to discourage him from getting into fights with the other children. - Negative Punishment

Ted increases paying his bills on time to avoid a late fee. - Negative Reinforcement

Sally increases the amount of work she completes to receive more pay. - Positive Reinforcement

Explanation:

In operant conditioning, the main principle is that behavior increases or decreases its frequency depending on whether it's reinforced or punished. A behavior can be reinforced by giving something the subject appreciates, like more pay for their work (positive reinforcement) or taking away something they dislike, like late fees (negative reinforcement). Punishments work the same way, you can give something the subject dislikes, like a parking ticket, (positive punishment) or taking away something they like recess for a child. (negative punishment).

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Children learn to resolve conflicts from surrounding adults.

sergij07 [2.7K]

Answer:

It is true that children learn to resolve conflicts from surrounding adults.

Explanation:

The environment where the children are raised reflects their decision making abilities and conflicts handling power.
Children are the best imitators of the adult around them. From all the activities adults perform around them, they learn that and apply in their life.
So it is always best to take care of our activities that we perform in front of our children.

4 0

4 years ago

What is a unit of mass?

Degger [83]

Units such as kilograms (about 2.2 pounds)n which are a thousand grams,grams,centigrams (hundredths of grams), and milligrams (thousands of grams).

3 0

3 years ago

Block A can slide relative to block B which, in turn, can slide on a perfectly smooth horizontal plane. If the initial velocity

Anna11 [10]

Answer:

the final velocity of the two blocks is $v = \frac{mv_o}{m+M}$

the distance that A slides relative to B is $S = \frac{v_o^2M}{2 \mu g (M+m)}$

Explanation:

From the diagram below;

acceleration of A relative to B is : $a = - ( \mu g + \frac{ \mu mg}{M})$

where

v = u + at

$0 = v_o + ( - \mu g - \frac{\mu m g }{M})t$

Making t the subject of the formula; we have:

$t = \frac{v_o M}{(\mu g )(M+m)}$

$v^2 = u^2 +2 as\\\\0^2 = v_o^2 - 2 (\mu g ) (\frac{M+m}{M})S\\\\$

$S = \frac{v_o^2M}{2 \mu g (M+m)}$ which implies the distance that A slides relative to B.

The final velocities of the two blocks can be determined as follows:

v = u + at

$v = v_o - \mu g \frac{v_oM}{\mu g (M+m)}\\\\v = \frac{\mu g mv_o}{m+M}\\\\$

$v = \frac{mv_o}{m+M}$

Thus, the final velocity of the two blocks is $v = \frac{mv_o}{m+M}$

4 0

3 years ago

Show your workikkkkkkkk

Svet_ta [14]

Answer:

Explanation:

F = ma

<u>Assuming</u> the 20° is angle θ measured to the horizontal

mgsinθ - μmgcosθ = ma

g(sinθ - μcosθ) = a

at constant velocity, a = 0

g(sinθ - μcosθ) = 0

sinθ - μcosθ = 0

sinθ = μcosθ

μ = sinθ/cosθ

μ = tanθ

μ = tan20

μ = 0.3639702342...

μ = 0.36

6 0

3 years ago

A 15.0 Ohms resistor is connected in series to a 120V generator and two 10.0 Ohms resistors that are connected in parallel to ea

Nostrana [21]

Hi there! :)

Reference the diagram below for clarification.

We must begin by knowing the following rules for resistors in series and parallel.

In series:
$R_T = R_1 + R_2 + ... + R_n$

In parallel:
$\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2} + ... + \frac{1}{R_n}$

We can begin solving for the equivalent resistance of the two resistors in parallel using the parallel rules.

$\frac{1}{R_{T, parallel}} = \frac{1}{10} + \frac{1}{10}\\\\\frac{1}{R_{T, parallel}} = \frac{2}{10} = \frac{1}{5}\\\\R_{T, parallel} = 5\Omega$

Now that we have reduced the parallel resistors to a 'single' resistor, we can add their equivalent resistance with the other resistor in parallel (15 Ohm) using series rules:
$R_T = 15 + 5\\\\\boxed{R_T = 20 \Omega}$

We can use Ohm's law to solve for the current in the circuit.

$i = \frac{V}{R_T}\\\\i = \frac{120}{20} = \boxed{6 A}$

For resistors in series, both resistors receive the SAME current.

Therefore, the 15Ω resistor receives 6A, and the parallel COMBO (not each individual resistor, but the 5Ω equivalent when combined) receives 6A.

In this instance, since both of the resistors in parallel are equal, the current is SPLIT EQUALLY between the two. (Current in parallel ADDS UP). Therefore, an even split between 2 resistors of 6 A is <u>3A for each 10Ω resistor</u>.

Since the 15.0 Ω resistor receives 6A, we can use Ohm's Law to solve for voltage.

$V = iR\\\\V = (6)(15) = \boxed{90 V}$

4 0

2 years ago