<h2>
Hey There!</h2><h2>
_____________________________________</h2><h2>
Answer:</h2><h2 /><h2>

</h2><h2>
_____________________________________</h2>
<h2>DATA:</h2>
mass = m = 2kg
Distance = x = 6m
Force = 30N
TO FIND:
Work = W = ?
Velocity = V = ?
<h2>
SOLUTION:</h2>
According to the object of mass 2 kg travels a distance when the force was exerted on it. The graph between the Force and position was plotted which shows that 30 N of force was used to push the object till the distance of 6.0m.
To find the work, I will use the method of determining the area of the plotted graph. As the graph is plotted in the straight line between the Force and work, THE PICTURE ATTCHED SHOWS THE AREA COVERED IN BLUE AS WORK DONE AND HEIGHT AS 30m AND DISTANCE COVERED AS 6m To solve for the area(work) of triangle is given as,

Base is the x-axis of the graph which is Position i.e. 6m
Height is the y-axis of the graph which is Force i.e. 30N
So,

W = 90 J
The work done is 90 J.
According to the principle of work and kinetic energy (also known as the work-energy theorem) states that the work done by the sum of all forces acting on a particle equals the change in the kinetic energy of the particle.



<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2>
Elastic
Explanation is that it is force which is snapping back
Answer and Explanation:
Data provided in the question
Force = 50N
Length = 5mm
diameter = 2.0m = 
Extended by = 0.25mm = 
Based on the above information, the calculation is as follows
a. The Stress of the wire is

here area of circle = perpendicular to the are i.e cross-sectional i.e
= 
= 
Now place these above values to the above formula

= 15.92 MPa
As 1Pa = 1 by N m^2
So,
MPa = 10^6 N m^2
b. Now the strain of the wire is

= 
Answer: He is usining
Gravity,Drag, Tension, Direction
Explanation: please give me brainliest
Answer:
Noise level will be -18.2 watt
So option (b) will be correct answer
Explanation:
We have given sound intensity 
And threshold intensity
( in question it is given as
but its standard value is
)
Now noise level 
So the noise level will be -18.2
So option (b) will be correct answer