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Paraphin [41]
3 years ago
13

The main energy source during exercise of low to moderate intensity is

Physics
1 answer:
zhannawk [14.2K]3 years ago
6 0

Answer:

THUS,THE MAJOR SOURCES OF ENERGY DURING EXERCISE ARE CARBOHYDRATES AND FATS.

Explanation:

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A disk of radius R = 9.54 cm, is centered at the origin and lies along the y–z plane. The disk has a surface charge density σ
lyudmila [28]

Answer:

Electric field by charged disk is given as

E = (Charge Density/2u0)*[1 - (z/sqrt(z^2 - R^2))]

R = 9.54cm = 0.0954m, z = 1.01m, Charge density = 4.07 x 10^-6C/m2, e0 = 8.85 x 10^-12F/m.

Substituting all the values in to equation,

E = (2.299 x 10^5) x (8.931 x 10^-3)

E = 2.053 x 10^3N/C

Explanation:

3 0
3 years ago
Are the small sized gears only force, speed and distance, only speed
sesenic [268]
If the gears are of different sizes, they can be used to increase the power of a turning force. The smaller wheel turns more quickly but with less force, while the bigger one turns more slowly with more force. Cars and bicycles use gears to achieve amazing speeds our bodies could never match without help.

3 0
3 years ago
Find the required angular speed, ω, of an ultracentrifuge for the radial acceleration of a point 1.80 cm from the axis to equal
Arturiano [62]

Answer:

The required angular speed ω of an ultra-centrifuge is:

ω = 18074 rad/sec

Explanation:

Given that:

Radius = r = 1.8 cm

Acceleration due to g = a = 6.0 x 10⁵ g

Sol:

We know that

Angular Acceleration = Angular Radius x Speed²

a = r x ω ²

Putting the values

6 x 10⁵ g = 1.8 cm x ω ²

Converting 1.8 cm to 0.018 m, also g = 9.8 ms⁻²

6 x 10⁵ x 9.8 = 0.018 x ω ²

ω ² = (6 x 10⁵ x 9.8) / 0.018

ω ² =  5880000 / 0.018

ω ² =  326666667

ω = 18074 rad/sec

7 0
3 years ago
When writing a number in scientific notation, how many digits should be to
Afina-wow [57]

Answer:

C

Explanation:

6 0
3 years ago
Read 2 more answers
The mass of the Sun is 2 × 1030 kg, the mass of the Earth is 6 × 1024 kg, and their center-to-center distance is 1.5 × 1011 m. S
choli [55]

Answer:

0.00461031264 m/s

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

M = Mass of the Earth =  6 × 10²⁴ kg

r = Distance between Earth and Sun = 1.5\times 10^{11}\ m

t = Time taken = 3 days

Acceleration is given by

a=\dfrac{GM}{r^2}\\\Rightarrow a=\dfrac{6.67\times 10^{-11}\times 6\times 10^{24}}{(1.5\times 10^{11})^2}\\\Rightarrow a=1.77867\times 10^{-8}\ m/s^2

Velocity of the star

v=u+at\\\Rightarrow v=0+1.77867\times 10^{-8}\times 3\times 24\times 60\times 60\\\Rightarrow v=0.00461031264\ m/s

The Sun's speed will be 0.00461031264 m/s

5 0
3 years ago
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