Answer:
126.99115 g
Explanation:
50 g at 90 cm
Stick balances at 61.3 cm
x = Distance of the third 0.6 kg mass
Meter stick hanging at 50 cm
Torque about the support point is given by (torque is conserved)

The mass of the meter stick is 126.99115 g
Answer:
The moment of inertia is 
Explanation:
From the question we are told that
The frequency is 
The mass of the pendulum is 
The location of the pivot from the center is 
Generally the period of the simple harmonic motion is mathematically represented as

Where I is the moment of inertia about the pivot point , so making I the subject of the formula it
=> ![I = [ \frac{T}{2 \pi } ]^2 * m* g * d](https://tex.z-dn.net/?f=I%20%3D%20%20%5B%20%5Cfrac%7BT%7D%7B2%20%5Cpi%20%7D%20%5D%5E2%20%2A%20%20m%2A%20%20g%20%2A%20d)
But the period of this simple harmonic motion can also be represented mathematically as

substituting values


So
![I = [ \frac{2.174}{2 * 3.142 } ]^2 * 2.40* 9.8 * 0.380](https://tex.z-dn.net/?f=I%20%3D%20%20%5B%20%5Cfrac%7B2.174%7D%7B2%20%2A%203.142%20%7D%20%5D%5E2%20%2A%20%20%202.40%2A%20%209.8%20%2A%200.380)

Answer:
The time it takes the proton to return to the horizontal plane is 7.83 X10⁻⁷ s
Explanation:
From Newton's second law, F = mg and also from coulomb's law F= Eq
Dividing both equations by mass;
F/m = Eq/m = mg/m, then
g = Eq/m --------equation 1
Again, in a projectile motion, the time of flight (T) is given as
T = (2usinθ/g) ---------equation 2
Substitute in the value of g into equation 2

Charge of proton = 1.6 X 10⁻¹⁹ C
Mass of proton = 1.67 X 10⁻²⁷ kg
E is given as 400 N/C, u = 3.0 × 10⁴ m/s and θ = 30°
Solving for T;

T = 7.83 X10⁻⁷ s
Answer:
10km/h
Explanation:
25÷2.5=10
speed = distance/time
velocity is a magnitude and needs a direction which wasnt provided so its basically the same as the speed