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Reika [66]
3 years ago
11

The earth's magnetic field deflects the flow of current from?

Physics
1 answer:
alexgriva [62]3 years ago
7 0
I don't really know the answer but maybe north pole and south pole?
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A meter stick balances at the 50.0-cm mark. If a mass of 50.0 g is placed at the 90.0-cm mark, the stick balances at the 61.3-cm
Airida [17]

Answer:

126.99115 g

Explanation:

50 g at 90 cm

Stick balances at 61.3 cm

x = Distance of the third 0.6 kg mass

Meter stick hanging at 50 cm

Torque about the support point is given by (torque is conserved)

mgl_1=Mgl_2\\\Rightarrow M=\dfrac{ml_1}{l_2}\\\Rightarrow M=\dfrac{50\times (61.3-90)}{50-61.3}\\\Rightarrow M=126.99115\ g

The mass of the meter stick is 126.99115 g

6 0
2 years ago
Read 2 more answers
Plz guys answer my question
Sophie [7]

Answer:

Explanation:

whats your question?

6 0
2 years ago
Read 2 more answers
A physical pendulum in the form of a planar object moves in simple harmonic motion with a frequency of 0.460 Hz. The pendulum ha
zlopas [31]

Answer:

The  moment of inertia is  I =1.0697 \ kg m^2

Explanation:

From the question we are told that

    The  frequency is  f  =  0.460 \ Hz

    The  mass of the pendulum is  m  =  2.40  \ kg

    The  location of the pivot from the center is d  =  0.380 \ m

     

Generally the period of the simple harmonic motion is mathematically represented as

        T   = 2 \pi  *  \sqrt{  \frac{I}{ m  *  g *  d  } }

Where I is the moment of inertia about the pivot point , so making I the subject of the formula it

=>    I =  [ \frac{T}{2 \pi } ]^2 *  m*  g * d

But the period of this simple harmonic motion can also be represented mathematically as

        T  =  \frac{1}{f}

substituting values

      T  =  \frac{1}{0.460}

      T  =  2.174 \ s

So

      I =  [ \frac{2.174}{2 * 3.142 } ]^2 *   2.40*  9.8 * 0.380

      I =1.0697 \ kg m^2

4 0
2 years ago
A proton moving at 3.0 × 10^4 m/s is projected at an angle of 30° above a horizontal plane. If an electric field of 400 N/C is a
GuDViN [60]

Answer:

The time it takes the proton to return to the horizontal plane is 7.83 X10⁻⁷ s

Explanation:

From Newton's second law, F = mg and also from coulomb's law F= Eq

Dividing both equations by mass;

F/m = Eq/m = mg/m, then

g = Eq/m --------equation 1

Again, in a projectile motion, the time of flight (T) is given as

T = (2usinθ/g) ---------equation 2

Substitute in the value of g into equation 2

T = \frac{2usin \theta}{\frac{Eq}{m}} =\frac{m* 2usin \theta}{Eq}

Charge of proton = 1.6 X 10⁻¹⁹ C

Mass of proton = 1.67 X 10⁻²⁷ kg

E is given as 400 N/C, u = 3.0 × 10⁴ m/s and θ = 30°

Solving for T;

T = \frac{(1.67X10^{-27}* 2*3X10^4sin 30}{400*1.6X10^{-19}}

T = 7.83 X10⁻⁷ s

6 0
2 years ago
Jessica jogs on a path that is 25 km long to get to the park that is south of the jogging path if it takes just a cut 2.5 hours
Vinil7 [7]

Answer:

10km/h

Explanation:

25÷2.5=10

speed = distance/time

velocity is a magnitude and needs a direction which wasnt provided so its basically the same as the speed

8 0
2 years ago
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