Answer is: 73.52 kJ<span> of energy is required to vaporize butane.
</span>m(C₄H₁₀) = 185 g.
n(C₄H₁₀) = m(C₄H₁₀) ÷ M(C₄H₁₀).
n(C₄H₁₀) = 185 g ÷ 58.12 g/mol.
n(C₄H₁₀) = 3.18 mol; amount of butane.
Hvap = 23.1 kJ/mol; <span>the heat of vaporization for butane.
</span>Q = Hvap · n(C₄H₁₀).
Q = 23.1 kJ/mol · 3.18 mol; energy.
Q = 73.52 kJ.
Wen a liquid turns into solid it loses thermal energy
D freezing
Answer:
its the 3rd option.
the molecules move from region of higher concentration to a region of lower concentration.
Explanation:
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Answer:
TRY HARD!
Explanation:
DO UR WORK ANG GET IT DONE!
