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3 years ago

How may sun are in earth

Chemistry

1 answer:

sashaice [31]3 years ago

6 0

Huh ?!?!???...............

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Which statements describe elements?

monitta

Answer: B,C,D

Explanation: Who ever reads this have a great day and stay safe :}

8 0

3 years ago

Read 2 more answers

The reaction of nitrogen gas and oxygen gas to form nitrogen monoxide gas is shown below. If the measured concentrations of all

Anettt [7]

Answer:

The forward reaction is occurring at a faster rate than the reverse reaction.

Explanation:

Reaction quotient (Q) of the given reaction is -

$Q=\frac{[NO]^{2}}{[N_{2}][O_{2}]}$

where [NO], $[N_{2}]$ and $[O_{2}]$ represents concentrations of respective species at a certain time.

Here $[N_{2}]$ = 0.80 M, $[O_{2}]$ = 0.050 M and [NO] = 0.10 M

So, $Q=\frac{(0.10)^{2}}{(0.80)\times (0.050)}=2$

Hence $Q> K$

It means that forward reaction is faster than reverse reaction at that point. Because then only concentration of NO is higher than concentrations of $[N_{2}]$ and $[O_{2}]$ which makes Q higher than K.

4 0

3 years ago

Plz answer asap !!!!

Semmy [17]

Answer:it's c

Explanation:

6 0

3 years ago

By the reaction of carbon & oxygen , a mixture of CO &CO2 is obtained. What is the composition by mass of the mixture ob

Hatshy [7]

M(O₂)=20g
M(O₂)=32.0 g/mol
n(O₂)=20/32.0=0.625 mol

m(C)=12 g
M(C)=12.0 g/mol
n(C)=12/12.0=1.0 mol

2C + O₂ → 2CO
1 mol 0.625 mol 1 mol
0.625-0.5=0.125 mol

2CO + O₂ → 2CO₂
0.250 mol 0.125 mol 0.250 mol

n(CO)=1 mol - 0.250 mol = 0.750 mol
M(CO)=28.0 g/mol
m(CO)=0.750*28.0=21.0 g

n(CO₂)=0.250 mol
M(CO₂)=44.0 g/mol
m(CO₂)=0.250*44.0=11.0 g

4 0

3 years ago

A container of carbon dioxide has a volume of 240 mL at a temperature of 22°C. If the pressure remains constant, what is the vol

astraxan [27]

Answer:

Volume of the $CO_{2}$ gas at 44°C is <u>258 ml.</u>

Explanation

here,

using Charles' law ,

$\frac{V}{T} =\frac{v}{t}$

where , V= initial volume v= final volume

T=initial temperature t = final temperature

Given - pressure is constant ,

so , putting the values -

V= 240ml

T= 22 + 273K = 295K (since converting celsius into kelvin that

is +273K )

v =?

t = 44+ 273K = 317K

Now , putting the given values in charles' law ,

$\frac{240ml}{295K} =\frac{v}{317K}$

240ml x317K = v x 295K (through cross multiplication )

v = $\frac{240ml\times317K}{295K}$

= 258ml .

thus ,<u> the volume of carbon dioxide in a container at 44°C IS 258ml .</u>

7 0

3 years ago