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AnnyKZ [126]
3 years ago
15

How is the energy of the universe conserved during the combustion of gasoline in a car engine?

Chemistry
2 answers:
ExtremeBDS [4]3 years ago
8 0

The energy produced during combustion of gasoline in a car engine is converted as kinetic energy.

Explanation

The conservation of energy clearly states that "energy can neither be created nor be destroyed , it can only be transferred from one form to another form".

The combustion of gasoline in a car engine tends to generate heat energy, this heat energy will be transferred as kinetic energy which will lead to motion of cars.

This the energy of the universe will be conserved as the energy created by the combustion is used as kinetic energy for movement of cars.

Marianna [84]3 years ago
6 0
In a car driven by a gasoline combustion engine, heat energy is quickly converted into kinetic energy which results in the motion of the car.

According to the law of the conservation of energy, energy cannot be destroyed or created. It is can only be transformed from one form to another.
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Chemical equation for hydrogen chloride dissolving in water
irga5000 [103]

Answer:

The answer is HCl → H 2 O H+ + Cl.

7 0
4 years ago
Although both N2 and 02 are naturally present in the air we breathe, high levels of NO and NO2 in the atmosphere occur mainly in
joja [24]

Answer:

(a) Increasing the temperature adds heat which is a reactant shifting the equilibrium rightwards.

(b) Pressure has no effect since the change in the number of moles is zero.

Explanation:

Hello,

In this case, one could represent the given reaction as:

N_2(g)+O_2(g)+ \Delta _rH \leftrightarrow 2NO

Since it is endothermic. Thus, solving the (a) statement, one identifies the heat as a reagent, that is why the reaction cools down as it progress, therefore, by increasing the temperature, heat is added, that is, a reagent is added, which shifts the equilibrium rightwards, in other words, more NO is produced so its concentration increases.

Furthermore, for the (b) statement, since the change in the number of moles is zero, based on the stoichiometric coefficients as shown below:

\Delta \nu =2-1-1=0

Such value implies that the pressure has no effect on the concentration, taking into account the following form of the law of mass action:

Kp=Kc(RT)^{\Delta \nu }

Thus, since \Delta \nu =0, Kp=Kc, so no effect in concentration is due to the pressure.

Best regards.

6 0
3 years ago
calculate the mass of butane needed to produce 64.1 g of carbon dioxide to three significant figures and appropriate units
cricket20 [7]

Answer:

21.2 gm

Explanation:

calculate the mass of butane needed to produce 64.1 g of carbon dioxide to three significant figures and appropriate units

butane is the hydrocarbon C4H10  

in combustion, we react hydrocarbons with O2 to form CO2 and H2O

so

C4H10  + O2---------------->  CO2 + H2O

BALANCE

2C4H10 + 1302--------> 8CO2 + 10 H2O

the molar mass of CO2 is 12 + 16X2 = 44

64.1 gm of CO2 is

64.1/44 = 1.46 MOLES OF  CO2,

FOR EVERY 8 MOLES OF CO2 WE NEED 2 MOLES OF BUTANE  IT IS A

8:2 OR 4:1 RATIO.  THE MOLES OF C4H10 ARE 1/4 THE MOLES OF CO2

SO

THE MOLES OF C4H10 H10 ARE 1.46/4 =0.365 MOLES

THE MOLAR MASS OF BUTANE IS 58.12

0.365 MOLES OF C4H10 HAS A MASS OF 0.365 X 58.12 = 21.2 gm

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3 years ago
Given: glow is a find the indicated measure.​
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Answer:

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Explanation:

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Answer:

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Explanation:

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4 years ago
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