How is the energy of the universe conserved during the combustion of gasoline in a car engine?

Chemistry

2 answers:

ExtremeBDS [4]3 years ago

8 0

The energy produced during combustion of gasoline in a car engine is converted as kinetic energy.

Explanation

The conservation of energy clearly states that "energy can neither be created nor be destroyed , it can only be transferred from one form to another form".

The combustion of gasoline in a car engine tends to generate heat energy, this heat energy will be transferred as kinetic energy which will lead to motion of cars.

This the energy of the universe will be conserved as the energy created by the combustion is used as kinetic energy for movement of cars.

Marianna [84]3 years ago

6 0

In a car driven by a gasoline combustion engine, heat energy is quickly converted into kinetic energy which results in the motion of the car.

According to the law of the conservation of energy, energy cannot be destroyed or created. It is can only be transformed from one form to another.

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A 19.0 L helium tank is pressurized to 26.0 atm. When connected to this tank, a balloon will inflate because the pressure inside

vesna_86 [32]

Answer:

The new volume of the balloon when the pressure equalised with the pressure of the atmosphere = 494 L.

The balloon expands by am additional 475 L.

Explanation:

Assuming Helium behaves like an ideal gas and temperature is constant.

According to Boyle's law for ideal gases, at constant temperature,

P₁V₁ = P₂V₂

P₁ = 26 atm

V₁ = 19.0 L

P₂ = 1 atm (the balloon is said to expand till the pressure matches the pressure of the atmpsphere; and the pressure of the atmosphere is 1 atm)

V₂ = ?

P₁V₁ = P₂V₂

(26 × 19) = 1 × V₂

V₂ = 494 L (it is assumed the balloon never bursts)

The new volume of the balloon when the pressure equalised with the pressure of the atmosphere = 494 L.

The balloon expands by am additional 475 L.

Hope this Helps!!!

6 0

3 years ago

What product or ratio of properties remains constant (PxT, TxV, P/V, V/T, etx)?When you have decided, label the "constant?" colu

Naddika [18.5K]

Answer:

In this phenomenon we talk about ideal gases, that is why in these equations the constant is the number of moles and the constant R, which has a value of 0.082

Explanation:

The complete equation would have to be P x V = n x R x T

where n is the number of moles, and if it is not clarified it is because they remain constant, as the question was worded.

On the other hand, the symbol R refers to the ideal gas constant, which declares that a gas behaves like an ideal gas during the reaction, and its value will always be the same, which is why it is called a constant. The value of R = 0.082.

The ideal gas model assumes that the volume of the molecule is zero and the particles do not interact with each other. Most real gases approach this constant within two significant figures, under pressure and temperature conditions sufficiently far from the liquefaction or sublimation point. The real gas equations of state are, in many cases, corrections to the previous one.

The universal constant of ideal gases is not a fundamental constant (therefore, choosing the temperature scale appropriately and using the number of particles, we can have R = 1, although this system of units is not very practical)

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3 years ago

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Anon25 [30]

Answer : The chemical formula for the compound is, $MI$