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Dafna11 [192]
3 years ago
11

Let point C be on circle A. If ∠BAC 5 radians and segment BC is 12cm, what is the length of the radius

Mathematics
1 answer:
Genrish500 [490]3 years ago
5 0

Answer:

2.4 cm

Step-by-step explanation:

The formula we would use

S = rθ

Where S = Arc length

θ = central angle in radians

r = radius of the circle or length of the radius.

From the question, we can see that if

If C = a point on circle A

The Segment BC = The arc length of the circle = 12cm

∠BAC = central angle in radians = 5 radians.

Since, S = rθ,

Length of the radius = S/θ

= 12cm/5 radians

Length of the radius = 2.4 cm

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According to government data, 75% of employed women have never been married. Rounding to 4 decimal places, if 15 employed women
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We are given that According to government data, 75% of employed women have never been married.

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b. That at most 2 of them have never been married?

At most two means at x = 0 ,1 , 2

So,  P(X=r) =^{15}C_0 (0.75)^0 (0.25^{15-0}+^{15}C_1 (0.75)^1 (0.25^{15-1}+^{15}C_2 (0.75)^2 (0.25^{15-2}

 P(X=r) =(0.75)^0 (0.25^{15-0}+15 (0.75)^1 (0.25^{15-1}+\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{15-2})

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c. That at least 13 of them have been married?

P(x=13)+P(x=14)+P(x=15)

={15}C_{13}(0.75)^{13} (0.25^{15-13})+{15}C_{14} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})

=\frac{15!}{13!(15-13)!}(0.75)^{13} (0.25^{15-13})+\frac{15!}{14!(15-14)!} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})

=0.2360

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