Explanation:
Charles' law gives the relationship between the volume and the temperature of the gas. Mathematically,
Volume ∝ Temperature
i.e.
We have, V₁ = 1.6 L, T₁ = 278 K, T₂ = 253, V₂=?
So, the new volume is 1.45 L.
Answer:
Q = 4.056 J
∴ m = 406.0 mg = 0.406 g
∴ <em>C </em>= 1.85 J/g.K
∴ T1 = 33.5°C ≅ 306.5 K
∴ T2 = 38.9°C = 311.9 K
⇒ ΔT = 311.9 - 306.5 = 5.4 K
⇒ Q = (0.406 g)(1.85 J/gK)(5.4 K)
⇒ Q = 4.056 J
Energy
Value of equilibrium constant is 0.0888
Both and are gaseous. Hence equilibrium constant depends upon partial pressures of and .
Initially no and were present.
Hence mole fraction of and at equilibrium can be calculated from coefficient of and in balanced equation.
Mole fraction of = (number of moles of )/(total number of moles of and ) =
Let's assume both and behaves ideally.
Therefore partial pressure of , and P_{CO_{2}}= x_{CO_{2}}.P_{total}
Where x represents mole fraction
So,