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crimeas [40]
3 years ago
7

The struggle for existence against other members of an organisms species is

Chemistry
2 answers:
fomenos3 years ago
5 0
It is a natural selection
n200080 [17]3 years ago
4 0
It is Natural selection
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Which material is the lest likely to be recognized as a mixture by looking at it under a microscope ?
Lisa [10]
Hello,

The answer is option C <span>homogeneous mixture.

Reason:

The answer is option C because you can find </span><span>homogeneous mixtures anywhere for example: Vinegar. Its not option A because suspension is usually in elements but as not a mixture. Its not option B because a colloid is a measurement tool that allows to make compounds (mixtures).Its also not option D because those type o mixtures are hard to find in extreme weather conditions.

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit </span>
4 0
3 years ago
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Hi kay my account got deleted this is my new one
jek_recluse [69]

Answer:

hUh

Explanation:

3 0
3 years ago
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A 42.0 mL sample of an NaOH solution is placed in a flask with a few drops of phenolphthalein (indicator). If 11.7 mL of a 0.325
olganol [36]
Please like if you get the answer :)

8 0
2 years ago
10) At constant temperature, a mixture containing 0.500 M N2 and 0.800 M H2 in a reaction vessel reaches equilibrium. At equilib
jarptica [38.1K]

Answer:

The answer to the question is;

The equilibrium constant for the reaction is 0.278

Reversibility.

Explanation:

Initial concentration = 0.500 M N₂ and 0.800 M H₂

N₂ (g) + 3·H₂ (g) ⇔ 2·NH₃ (g)

One mole of nitrogen combines with three moles of hydrogen form 2 moles of ammonia

That is 1 mole of ammonia requires 3/2 moles of H₂ and 1/2 moles of N₂

0.150 M of ammonia requires 3/2×0.150 moles of H₂ and 1/2×0.150 moles of N₂

That is 0.150 M of ammonia requires 0.225 moles of H₂ and 0.075 moles of N₂

Therefore at equilibrium we have

Number of moles of Nitrogen = 0.500 M - 0.075 M = 0.425 M

Number of moles of Hydrogen = 0.800 M - 0.225 M = 0.575 M

Number of moles of Ammonia = 0.150 M

K_c = \frac{[NH_3]^2}{[N_2][H_2]^3} = \frac{(0.15)^2}{(0.425)*(0.575)^3}  = 0.278

The kind of reaction is a reversible one as the equilibrium constant is greater than 0.01 which as general guide, all components in a reaction with an equilibrium constant between the ranges of 0.01 and 100 will be present when equilibrium is reached and the chemical reaction will be reversible.

6 0
3 years ago
Read 2 more answers
2A + B + 2C ? D + E
Amanda [17]

Answer:

C Rate =k [A]^{2} [B][C]^{-1}

Explanation:

In order to determine the correct rate law, let's use Trial 1 as baseline. Therefore:

An increase in [A] in Trial 2 by a factor of \sqrt{2} leads to an increase in the rate of reaction by a factor of 2 (i.e. the reaction rate is doubled). Thus, there is second order in [A].

Similarly,

An increase in [B] in Trial 3 by a factor of 1.667 leads to an increase in the rate of reaction by a factor of 1.667. Thus, there is first order in [B].

Futhermore,

An increase in [C] in Trial 4 by a factor of 1.71 leads to a decrease in the rate of reaction by 1.71. Thus, there is inverse first order in [C].

Therefore, the correct rate law is:

Rate =k [A]^{2} [B][C]^{-1}

8 0
3 years ago
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