Hello,
The answer is option C <span>homogeneous mixture.
Reason:
The answer is option C because you can find </span><span>homogeneous mixtures anywhere for example: Vinegar. Its not option A because suspension is usually in elements but as not a mixture. Its not option B because a colloid is a measurement tool that allows to make compounds (mixtures).Its also not option D because those type o mixtures are hard to find in extreme weather conditions.
If you need anymore help feel free to ask me!
Hope this helps!
~Nonportrit </span>
Answer:
The answer to the question is;
The equilibrium constant for the reaction is 0.278
Reversibility.
Explanation:
Initial concentration = 0.500 M N₂ and 0.800 M H₂
N₂ (g) + 3·H₂ (g) ⇔ 2·NH₃ (g)
One mole of nitrogen combines with three moles of hydrogen form 2 moles of ammonia
That is 1 mole of ammonia requires 3/2 moles of H₂ and 1/2 moles of N₂
0.150 M of ammonia requires 3/2×0.150 moles of H₂ and 1/2×0.150 moles of N₂
That is 0.150 M of ammonia requires 0.225 moles of H₂ and 0.075 moles of N₂
Therefore at equilibrium we have
Number of moles of Nitrogen = 0.500 M - 0.075 M = 0.425 M
Number of moles of Hydrogen = 0.800 M - 0.225 M = 0.575 M
Number of moles of Ammonia = 0.150 M
K
=
= 0.278
The kind of reaction is a reversible one as the equilibrium constant is greater than 0.01 which as general guide, all components in a reaction with an equilibrium constant between the ranges of 0.01 and 100 will be present when equilibrium is reached and the chemical reaction will be reversible.
Answer:
C Rate ![=k [A]^{2} [B][C]^{-1}](https://tex.z-dn.net/?f=%3Dk%20%5BA%5D%5E%7B2%7D%20%5BB%5D%5BC%5D%5E%7B-1%7D)
Explanation:
In order to determine the correct rate law, let's use Trial 1 as baseline. Therefore:
An increase in [A] in Trial 2 by a factor of
leads to an increase in the rate of reaction by a factor of 2 (i.e. the reaction rate is doubled). Thus, there is second order in [A].
Similarly,
An increase in [B] in Trial 3 by a factor of 1.667 leads to an increase in the rate of reaction by a factor of 1.667. Thus, there is first order in [B].
Futhermore,
An increase in [C] in Trial 4 by a factor of 1.71 leads to a decrease in the rate of reaction by 1.71. Thus, there is inverse first order in [C].
Therefore, the correct rate law is:
Rate ![=k [A]^{2} [B][C]^{-1}](https://tex.z-dn.net/?f=%3Dk%20%5BA%5D%5E%7B2%7D%20%5BB%5D%5BC%5D%5E%7B-1%7D)