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astra-53 [7]
3 years ago
9

Which expression is equivalent to ((4^((5)/(4)).4^((1)/(4)))/(4^((1)/(2))))^((1)/(2))?

Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
6 0

Answer:  2

Step-by-step explanation:

The given expression : (\dfrac{4^{\frac{5}{4}}\cdot4^{\frac{1}{4}}}{4^{\frac{1}{2}}})^{\frac{1}{2}

Using product rule of exponents :

a^m\cdot a^n= a^{m+n}

we get

(\dfrac{4^{\frac{5}{4}}\cdot4^{\frac{1}{4}}}{4^{\frac{1}{2}}})^{\frac{1}{2}}\\\\=(\dfrac{4^{\frac{5}{4}+\frac{1}{4}}}{4^{\frac{1}{2}}})^{\frac{1}{2}}\\\\=(\dfrac{4^{\frac{5+1}{4}}}{4^{\frac{1}{2}}})^{\frac{1}{2}}\\

=(\dfrac{4^{\frac{3}{2}}}{4^{\frac{1}{2}}})^{\frac{1}{2}}

Using division rule of exponents :

\dfrac{a^m}{a^n} =a^{m-n}

(\dfrac{4^{\frac{3}{2}}}{4^{\frac{1}{2}}})^{\frac{1}{2}}=(4^{\frac{3}{2}-\frac{1}{2}})^{\frac{1}{2}}\\\\=(4^{\frac{3-1}{2}})^{\frac{1}{2}}\\\\=(4^{\frac{2}{2}})^{\frac{1}{2}}\\\\=(4^1})^{\frac{1}{2}}=(2\times 2)^{\frac{1}{2}}= (2^2)^{\frac{1}{2}}=2

Hence, the correct answer (\dfrac{4^{\frac{5}{4}}\cdot4^{\frac{1}{4}}}{4^{\frac{1}{2}}})^{\frac{1}{2}= 2

kotegsom [21]3 years ago
4 0
Well, this is a good practice of indices.

All of the numbers involved have the same base.

so, for the inner bracket, the powers will be (division is a minus sign for the powers):
\frac{5}{4}+\frac{1}{4}-\frac{1}{2}=1

So the inner value is
(4^{1})^{\frac{1}{2}}=4^{\frac{1}{2}} = 2
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