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Tatiana [17]
3 years ago
9

There are 20 wheels on a group of bicycles. Each bike has 2 wheels. How many bikes are there?​

Mathematics
1 answer:
Mashcka [7]3 years ago
3 0
Answer: 10

Explanation: Each bicycle has 2 wheels, if the total is 20 wheels you find the number that equals to 20 which is 10 × 2 = 20
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If (z°z)(x)=1/16x , what is z (x)?
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4 years ago
PLEASE HELP ME 10 POINTS!!!!!
NemiM [27]
The answer to your question would be 150 (c)
6 0
3 years ago
PLEASE HELP ME!
kotegsom [21]

Answer:

Bottom left graph

Step-by-step explanation:

We have to use what is called the zero-interval test [test point] in order to figure out which portion of the graph these inequalities share:

−2x + y ≤ 4 >> Original Standard Equation

+ 2x + 2x

_________

y ≤ 2x + 4 >> Slope-Intercept Equation

−2[0] + 0 ≤ 4

0 ≤ 4 ☑ [We shade the part of the graph that CONTAINS THE ORIGIN, which is the right side.]

\displaystyle y > x + 2 \\ \\ 0 ≯ 2[We shade the part of the graph that does not contain the origin, which is the left side.]

So, now that we got that all cleared up, we can tell that the graphs share a region in between each other and that they both have POSITIVE <em>RATE OF CHANGES</em> [<em>SLOPES</em>], therefore the bottom left graph matches what we want.

** By the way, you meant \displaystyle y > x + 2because this inequality in each graph is a <em>dashed</em><em> </em><em>line</em>. It is ALWAYS significant that you be very cautious about which inequalities to choose when graphing. Inequalities can really trip some people up, so once again, please be very careful.

I am joyous to assist you anytime.

7 0
4 years ago
G with the definition of covariance, prove cov[(ay − b),(cy − d)] = accov(x, y ), where x, y are random variables and a, b, c, d
____ [38]

By definition of covariance,


\mathrm{Cov}(X,Y)=\mathbb E[(X-\mathbb E[X])(Y-\mathbb E[Y])]


\mathrm{Cov}(X,Y)=\mathbb E[XY-\mathbb E[X]Y-X\mathbb E[Y]+\mathbb E[X]\mathbb E[Y]]=\mathbb E[XY]-\mathbb E[X]\mathbb E[Y]


We have


\mathbb E[(aX-b)(cY-d)]=\mathbb E[acXY-adX-bcY+bd]

=ac\mathbb E[XY]-ad\mathbb E[X]-bc\mathbb E[Y]+bd


\mathbb E[aX-b]=a\mathbb E[X]-b


\mathbb E[cY-d]=c\mathbb E[Y]-d


\mathbb E[aX-b]\mathbb E[cY-d]=ac\mathbb E[X]\mathbb E[Y]-ad\mathbb E[X]-bc\mathbb E[Y]+bd


Putting everything together, we find the covariance reduces to


\mathrm{Cov}(aX-b,cY-d)=ac(\mathbb E[XY]-\mathbb E[X]\mathbb E[Y])=ac\mathrm{Cov}(X,Y)


as desired.

5 0
3 years ago
In his coin box , Brian has 12 fewer nickels than dimes. The value of his nickels and dimes is 2.40. Determine the exact number
swat32

Answer:

There are 8 nickels, and 20 dimes.

5 0
3 years ago
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