Negative ions are attracted to the anode. In the process of electrolysis, current can flow through a liquid because negative ions are attracted to the anode.
The required mole ratio of NH₃ to N₂ in the given chemical reaction is 2:4.
<h3>What is the stoichiometry?</h3>
Stoichiometry of the reaction gives idea about the number of entities present on the reaction before and after the reaction.
Given chemical reaction is:
4NH₃ + 3O₂ → 2N₂ + 6H₂O
From the stoichiometry of the reaction it is clear that:
4 moles of NH₃ = produces 2 moles of N₂
Mole ratio NH₃ to N₂ is 2:4.
Hence required mole ratio is 2:4.
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Answer:
Explanation:
Problem 1
<u>1. Data</u>
<u />
a) P₁ = 3.25atm
b) V₁ = 755mL
c) P₂ = ?
d) V₂ = 1325 mL
r) T = 65ºC
<u>2. Formula</u>
Since the temeperature is constant you can use Boyle's law for idial gases:

<u>3. Solution</u>
Solve, substitute and compute:


Problem 2
<u>1. Data</u>
<u />
a) V₁ = 125 mL
b) P₁ = 548mmHg
c) P₁ = 625mmHg
d) V₂ = ?
<u>2. Formula</u>
You assume that the temperature does not change, and then can use Boyl'es law again.

<u>3. Solution</u>
This time, solve for V₂:

Substitute and compute:

You must round to 3 significant figures:

Problem 3
<u>1. Data</u>
<u />
a) V₁ = 285mL
b) T₁ = 25ºC
c) V₂ = ?
d) T₂ = 35ºC
<u>2. Formula</u>
At constant pressure, Charle's law states that volume and temperature are inversely related:

The temperatures must be in absolute scale.
<u />
<u>3. Solution</u>
a) Convert the temperatures to kelvins:
- T₁ = 25 + 273.15K = 298.15K
- T₂ = 35 + 273.15K = 308.15K
b) Substitute in the formula, solve for V₂, and compute:

You must round to two significant figures: 290 ml
Problem 4
<u>1. Data</u>
<u />
a) P = 865mmHg
b) Convert to atm
<u>2. Formula</u>
You must use a conversion factor.
Divide both sides by 760 mmHg

<u />
<u>3. Solution</u>
Multiply 865 mmHg by the conversion factor:

He can conclude that his experiment has very low precision.
<h3>What is Precision ?</h3>
Precision is defined as the degree of refinement with which an operation is performed or a measurement .
Precision is how close the exact answers are together.
As, the answers are increasing in time.
None of the answers are similar to one another.
Hence, He can conclude that his experiment has very low precision.
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Answer:
Explanation:
Moles of
= 1 mole
Moles of
= 1 mole
Volume of solution = 1 L
Initial concentration of
= 1 M
Initial concentration of
= 1 M
The given balanced equilibrium reaction is,

Initial conc. 1 M 0M 1 M
At eqm. conc. (1-2x) M (2x) M (1+x) M
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[NO]^2[Cl_2]}{[NOCl]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BNO%5D%5E2%5BCl_2%5D%7D%7B%5BNOCl%5D%5E2%7D)
The
= 
Now put all the given values in this expression, we get :

By solving the term 'x', we get :

Concentration of
at equilibrium= (2x) M =