Answer:

Explanation:
Hello,
In this case, given that the same temperature and pressure is given for all the gases, we can notice that 16.0 mL are related with two moles of carbon monoxide by means of the Avogadro's law which allows us to understand the volume-moles relationship as a directly proportional relationship. In such a way, since in the chemical reaction:

We notice two moles of carbon monoxide yield two moles of carbon dioxide, therefore we have the relationship:

Thus, solving for the yielded volume of carbon dioxide we obtain:

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Answer:
Answer is c the moon passes in between the sun and the earth.
Explanation:
I hope this helps.
Before mRNA leaves the nucleus of a eukaryotic cell, a cap is added to one end of the molecule, a poly A tail is added to the other end, introns are removed, and exons are spliced together. During translation the amino acids are assembled into a protein.
Answer:- 55 g of LiCl are required to make 2.0 L of 0.65 M solution.
Solution:- Given-
molarity of the solution = 0.65M
Volume of solution = 2.0 L
molarity of solution = 
It could be arranged as...
moles of solute = molarity x volume of solution
moles of solute = 0.65 x 2.0 = 1.3 moles
Molar mass of LiCl is 42.39 g/mol.
So, mass of LiCl required = 1.3 mol x 42.39g/mol = 55 g