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umka21 [38]
4 years ago
15

Pick an activity you enjoy, such as running or riding a scooter, and describe how newton's laws apply to that activity.

Physics
2 answers:
deff fn [24]4 years ago
5 0
I like playing basketball. So I'm the object in motion. Until an unbalanced force comes and hits me I fall and stay at rest. 
Solnce55 [7]4 years ago
4 0
If you are running, your feet always go down because of gravity, same with scootering, the scooter stays on the ground because of gravity, same with volleyball and any other sport. How you score in volleyball is when the ball hits the ground on the other team's side, when the ball finally falls to the ground, it is because of gravity
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B dropping a ball
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Two horizontal pipes have the same diameter, but pipe B is twice as long as pipe A. Water undergoes viscous flow in both pipes,
zheka24 [161]

Answer:

c) 2Q

Explanation:

From the given information:

The pressure inside a pipe can be expressed by using the formula:

\Delta P = \dfrac{128 \mu L Q}{\pi D^4}

Since the diameter in both pipes is the same, we can say:

D = D_A = D_B

where;

length of the first pipe A L_A = L and the length of the second pipe B L_B = 2L

Since the difference in pressure is equivalent in both pipes:

Then:

\dfrac{128 \mu L_1Q_1}{\pi D_1^4} = \dfrac{128 \mu L_2Q_2}{\pi D_2^4}

\dfrac{ L_1Q_1}{D_1^4} = \dfrac{ L_2Q_2}{D_2^4}

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\mathbf{Q_1 = 2Q}

6 0
3 years ago
When the compressor of an air conditioner starts up, it draws a current of 50 A. If the start-up time is 0.60 s, then the amount
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Answer:

30 C

Explanation:

Given:

Current flowing in the circuit (I) = 50 A

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Now, we know that, charge drawn in through a cross sectional area of the circuit is given as:

q=It

Where, 'q' is the amount of charge drawn, 'I' is the current and 't' is the start-up time.

Now, plug in 50 A for 'I', 0.60 s for 't' and solve for 'q'. This gives,

q=50\ A\times 0.60\ s\\\\q=30\ C

Therefore, the amount of charge drawn in the circuit at the start-up of the compressor of an air conditioner is 30 C.

6 0
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The vertical displacement of the wave is measured from the
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The vertical displacement of the wave is measured from
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