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4 years ago

Pick an activity you enjoy, such as running or riding a scooter, and describe how newton's laws apply to that activity.

2 answers:

5 0

I like playing basketball. So I'm the object in motion. Until an unbalanced force comes and hits me I fall and stay at rest.

Solnce55 [7]4 years ago

4 0

If you are running, your feet always go down because of gravity, same with scootering, the scooter stays on the ground because of gravity, same with volleyball and any other sport. How you score in volleyball is when the ball hits the ground on the other team's side, when the ball finally falls to the ground, it is because of gravity

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As a space shuttle climbs, _______

n200080 [17]

Rocket fuel will and smoke will emit from the thrusters.

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3 years ago

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An astronaut on a space walk floats a little too far away from the space station. Without air to push against, he cannot paddle

Artyom0805 [142]

He can throw the hammer in the direction opposite to the direction he wants to travel in. The hammer will exert an equal and opposite force on him, as per Newton's third law, and this will help him move towards the space station.

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3 years ago

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As Douglas considers his wife’s condition, he realizes that the change having the most impact is “the one that began to steal he

Tanya [424]

I believe that the loss of Phyllis' recollections is thought to be the most heartbreaking side effect of her ailment in light of the fact that once a man's memory scatters then piece of the individual begins to vanish with them. A memory holds a considerable measure of essential data, for example, people's identity, where They have lived, and their connections that they have had with individuals.

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3 years ago

One of the main factors driving improvements in the cost and complexity of integrated circuits (ICs) is improvements in photolit

nika2105 [10]

Answer:

0.000003782 m

0.000001891 m

0.000001197125 m

Explanation:

$\lambda$ = Wavelength = 248 nm

D = Diameter of beam = 1 cm

f = Focal length = 0.625 cm

The angle is given by

$\theta=\dfrac{1.22\lambda}{D}$

The width is given by

$d=2\theta f\\\Rightarrow d=2\dfrac{1.22\lambda f}{D}\\\Rightarrow d=2\dfrac{1.22\times 248\times 10^{-9}\times 6.25\times 10^{-2}}{1\times 10^{-2}}\\\Rightarrow d=0.000003782\ m$

The required width is 0.000003782 m

Minimum resolvable line separation is given by

$\dfrac{0.000003782}{2}=0.000001891\ m$

The minimum resolvable line separation between adjacent lines is 0.000001891 m

when $\lambda=157\ nm$

$d=2\dfrac{1.22\times 157\times 10^{-9}\times 6.25\times 10^{-2}}{1\times 10^{-2}}\\\Rightarrow d=0.00000239425\ m$

The new minimum resolvable line separation between adjacent lines is

$\dfrac{0.00000239425}{2}=0.000001197125\ m$

6 0

3 years ago

two toy cars can roll without friction on a horizontal surface. Car A is a 5 kg. Car B is 0.5 kg. Both cars start from rest. Equ

Llana [10]

Answer:

A. The momentum of car A(5kg) is EQUAL to that of car B(0.5)

Explanation:

The moment, or impulse formula of the same forces acting on both car within 1 second is

$\Delta p = F * \Delta t$

In our case the forces are the same, the time duration of force acting on the cars are the same. Therefore, their momentum right after the force must also be the same.

8 0

3 years ago