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anygoal [31]
3 years ago
15

A power transmission line is hung from metal towers with glass insulators having a resistance of 1.00×109 Ω . What current flows

through the insulator if the voltage is 200 kV? (Some high-voltage lines are DC.)
Physics
1 answer:
Hunter-Best [27]3 years ago
5 0

Answer:

The current flows through the insulator is 2 mA.

Explanation:

Given that,

Resistance R=1.00\times10^{9}\ \Omega

Voltage = 200 kV

We need to calculate the current

Using ohm's law

V=IR

I=\dfrac{V}{R}

Where, I = current

V = voltage

R = resistance

Put the value into the formula

I=\dfrac{200\times10^{3}}{1.00\times10^{9}}

I=0.0002\ A

I=2\ mA

Hence, The current flows through the insulator is 2 mA.

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Earth receives energy from the sun through what method of heat transfer?
Daniel [21]
Radiation that comes from the sun is being beemed at earth atmosphere
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3 years ago
Read 2 more answers
What traction of the radioisotope<br>remains in the body after one day?​
r-ruslan [8.4K]

The fraction of radioisotope left after 1 day is (\frac{1}{2})^{\frac{1}{\tau}}, with the half-life expressed in days

Explanation:

The question is incomplete: however, we can still answer as follows.

The mass of a radioactive sample after a time t is given by the equation:

m(t)=m_0 (\frac{1}{2})^{\frac{t}{\tau}}

where:

m_0 is the mass of the radioactive sample at t = 0

\tau is the half-life of the sample

This means that the mass of the sample halves after one half-life.

We can rewrite the equation as

\frac{m(t)}{m_0}=(\frac{1}{2})^{\frac{t}{\tau}}

And the term on the left represents the fraction of the radioisotope left after a certain time t.

Therefore, after t = 1 days, the fraction of radioisotope left in the body is

\frac{m(1)}{m_0}=(\frac{1}{2})^{\frac{1}{\tau}}

where the half-life \tau must be expressed in days in order to match the units.

Learn more about radioactive decay:

brainly.com/question/4207569

brainly.com/question/1695370

#LearnwithBrainly

5 0
3 years ago
An object is thrown off a cliff with a horizontal speed of 10 m/sec. After 3 seconds the object hits the ground. Find the height
Degger [83]

Answer:

223

Explanation:

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4 0
3 years ago
A person walks the path shown below. The total trip consists of four straight-line paths.
dmitriy555 [2]

At the end of the walk, the person's resultant displacement is 495.1 m at 63⁰ south of west.

<h3>What is resultant displacement?</h3>

The resultant displacement of an object is the change in position of the object. It can be described as the shortest distance connecting the final position of the object to the initial position of the object.

<h3>Net horizontal displacement </h3>

Path 1 = 40 m

Path 2 = 0 m

Path 3 = 110 m x cos(30) = 95.26 m

Path 4 = 180 m x cos(60) = 90 m

Total horizontal displacement, X = 40 m + 0 m + 95.26 m + 90 m = 225.26 m

<h3>Net vertical displacement </h3>

Path 1 = 0 m

Path 2 = 230 m

Path 3 = 110 m x sin(30) = 55 m

Path 4 = 180 m x sin(60) = 155.885 m

Total horizontal displacement, Y = 0 m + 230 m + 55 m + 155.885 m = 440.885 m

<h3>Resultant displacement</h3>

R = √(X² + Y²)

R = √(225.26² + 440.885²)

R = 495.1 m

<h3>Direction of the displacement</h3>

θ = arc tan (Y/X)

θ = arc tan (440.885/225.26)

θ =  63⁰

Thus, at the end of the walk, the person's resultant displacement is 495.1 m at 63⁰ south of west.

Learn more about resultant displacement here: brainly.com/question/13309193

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3 0
1 year ago
What is meant by radioactivity?
vladimir1956 [14]
What that means is the atom is so radioactive that the nucleus is unstable.

4 0
3 years ago
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