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anygoal [31]
3 years ago
15

A power transmission line is hung from metal towers with glass insulators having a resistance of 1.00×109 Ω . What current flows

through the insulator if the voltage is 200 kV? (Some high-voltage lines are DC.)
Physics
1 answer:
Hunter-Best [27]3 years ago
5 0

Answer:

The current flows through the insulator is 2 mA.

Explanation:

Given that,

Resistance R=1.00\times10^{9}\ \Omega

Voltage = 200 kV

We need to calculate the current

Using ohm's law

V=IR

I=\dfrac{V}{R}

Where, I = current

V = voltage

R = resistance

Put the value into the formula

I=\dfrac{200\times10^{3}}{1.00\times10^{9}}

I=0.0002\ A

I=2\ mA

Hence, The current flows through the insulator is 2 mA.

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ii) m = \frac{W}{g} ⇒ m = 108 ÷ 10 = 10.8 kg , F = ma ⇒ F = 10.8 × 5 = 54 N

iii) F1 = F2 = 54 N

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When the speed of the bottle is 2 m/s, the KE is kg m2/s2. When the speed of the bottle is 3 m/s, the KE is kg m2/s2. When the s
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mass of the bottle in each case is M = 0.250 kg

now as per given speeds we can use the formula of kinetic energy to find it

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2) when speed is 3 m/s

kinetic energy is given as

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3) when speed is 4 m/s

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kinetic energy is given as

K = \frac{1}{2}mv^2

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