Answer:
71.4583 Hz
67.9064 N
Explanation:
L = Length of tube = 1.2 m
l = Length of wire = 0.35 m
m = Mass of wire = 9.5 g
v = Speed of sound in air = 343 m/s
The fundamental frequency of the tube (closed at one end) is given by

The fundamental frequency of the wire and tube is equal so he fundamental frequency of the wire is 71.4583 Hz
The linear density of the wire is

The fundamental frequency of the wire is given by

The tension in the wire is 67.9064 N
Answer:
The minimum thickness of the film and the wavelength of the light in air are
and 371 nm.
Explanation:
Given that,
Refractive index of soap= 1.34
Refractive index of glass= 1.55
Wavelength = 642 nm
(I). We need to calculate the minimum thickness
Using formula of thickness

Where, m = 0 for constrictive
Put the value into the formula


(II). We need to calculate the wavelength
Using formula of wavelength

Where, m = 1
Put the value into the formula


Hence, The minimum thickness of the film and the wavelength of the light in air are
and 371 nm.
Answer:
the Corona is about 10 million times less dense than sun's surface.this low density makesuch less bright than surface of the sun
It is 66.1 :) You multiply all of them together