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Nookie1986 [14]

3 years ago

15

When a substance changes states, it either or energy

1 answer:

liubo4ka [24]3 years ago

8 0

Explanation:

Energy is always involved in changes of state. Matter either loses or absorbs energy when it changes from one state to another. For example, when matter changes from a liquid to a solid, it loses energy. The opposite happens when matter changes from a solid to a liquid.

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A tube 1.20 m long is closed at one end. A stretched wire is placed near the open end. The wire is 0.350 m long and has a mass o

Ksju [112]

Answer:

71.4583 Hz

67.9064 N

Explanation:

L = Length of tube = 1.2 m

l = Length of wire = 0.35 m

m = Mass of wire = 9.5 g

v = Speed of sound in air = 343 m/s

The fundamental frequency of the tube (closed at one end) is given by

$f=\frac{v}{4L}\\\Rightarrow f=\frac{343}{4\times 1.2}\\\Rightarrow f=71.4583\ Hz$

The fundamental frequency of the wire and tube is equal so he fundamental frequency of the wire is 71.4583 Hz

The linear density of the wire is

$\mu=\frac{m}{l}\\\Rightarrow \mu=\frac{9.5\times 10^{-3}}{0.35}\\\Rightarrow \mu=0.02714\ kg/m$

The fundamental frequency of the wire is given by

$f=\frac{1}{2l}\sqrt{\frac{T}{\mu}}\\\Rightarrow f^2=\frac{1}{4l^2}\frac{T}{\mu}\\\Rightarrow T=f^2\mu 4l^2\\\Rightarrow T=71.4583^2\times 0.02714\times 4\times 0.35^2\\\Rightarrow T=67.9064\ N$

The tension in the wire is 67.9064 N

7 0

3 years ago

A thin film of soap with n = 1.34 hanging in the air reflects dominantly red light with λ = 642 nm. What is the minimum thicknes

wariber [46]

Answer:

The minimum thickness of the film and the wavelength of the light in air are $1.197\times10^{-7}\ m$ and 371 nm.

Explanation:

Given that,

Refractive index of soap= 1.34

Refractive index of glass= 1.55

Wavelength = 642 nm

(I). We need to calculate the minimum thickness

Using formula of thickness

$t=\dfrac{(2m+1)\lambda}{4n}$

Where, m = 0 for constrictive

Put the value into the formula

$t=\dfrac{(642\times10^{-9})}{4\times1.34}$

$t=1.197\times10^{-7}\ m$

(II). We need to calculate the wavelength

Using formula of wavelength

$\lambda=\dfrac{2nt}{m}$

Where, m = 1

Put the value into the formula

$\lambda=\dfrac{2\times1.55\times1.197\times10^{-7}}{1}$

$\lambda=371\ nm$

Hence, The minimum thickness of the film and the wavelength of the light in air are $1.197\times10^{-7}\ m$ and 371 nm.

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bogdanovich [222]

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