Answer:
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Explanation:
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Answer:
The system's potential energy is -147 J.
Explanation:
Given that,
Energy = 147 J
We know that,
System is isolated and it is free from external forces.
So, the work done by the external forces on the system should be equal to zero.
![W=0](https://tex.z-dn.net/?f=W%3D0)
We need to calculate the system's potential energy
Using thermodynamics first equation
![\Delta U=W-\Delta E](https://tex.z-dn.net/?f=%5CDelta%20U%3DW-%5CDelta%20E)
Put the value into the formula
![\Delta U=0-147](https://tex.z-dn.net/?f=%5CDelta%20U%3D0-147)
![\Delta U=-147\ J](https://tex.z-dn.net/?f=%5CDelta%20U%3D-147%5C%20J)
Hence, The system's potential energy is -147 J.
Answer:
A body travels 10 meters during the first 5 seconds of its travel,and a total of 30 meters over the first 10 seconds of its travel
20miles / 5sec = 4miles /sec would be the average speed for the last 20 m
Explanation:
The answer is 4 m/s.
In the first 5 seconds, a body travelled 10 meters. In the first 10 seconds of the travel, the body travelled a total of 30 meters, which means that in the last 5 seconds, it travelled 20 meters (30m + 10m).
The relation of speed (v), distance (d), and time (t) can be expressed as:
v = d/t
We need to calculate the speed of the second 5 seconds of the travel:
d = 20 m (total 30 meters - first 10 meters)
t = 5 s (time from t = 5 seconds to t = 10 seconds)
Thus:
v = 20m / 5s = 4 m/s
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