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skad [1K]
3 years ago
13

Calculate the amount of heat required to heat a 3.3 kg gold bar from 26 ∘C to 69 ∘C. Specific heat capacity of gold is 0.128 J/g

∘C.
Chemistry
2 answers:
kaheart [24]3 years ago
6 0
To answer the question above, we make use of the equation,
                          heat = (specific heat ) x mass x (change in temperature)
Substituting the known values,
                       heat = (0.128 J/g°C) x (3.3 kg)(1000g / 1kg) x (69°C - 26°C)
                               = 18163.2 J
Therefore, the amount of heat required is approximately 18163.2 J. 
Olin [163]3 years ago
6 0

Answer:

We need 18.2 kJ of heat

Explanation:

Step 1: Data given

Mass of gold = 3.3 kg = 3300 grams

Initial temperature = 26.0 °C

Final temperature = 69.0 °C

Specific heat of gold = 0.128 J/g°C

Step 2: Calculate the heat

Q = m*c*ΔT

⇒ with Q = the heat transfered = TO BE DETERMINED

⇒ with m = the mass of gold = 3300 grams

⇒ with c = the specific heat of gold = 0.128 J/g°C

⇒ with ΔT = The change in temperature = T2 - T1 = 69.0 - 26.0 = 43.0 °C

Q = 3300g * 0.128 J/g°C * 43.0 °C

Q = 18163 J = 18.2 kJ

We need 18.2 kJ of heat

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Answer:

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Explanation:

¡Hola!

En este caso, teniendo en cuenta la descripción inicial de la sustancia, la cual se torna violeta cuando se le agrega la fenolftaleína, es posible inderir que esta sustancia es una base con pH básico. Ahora bien, en torno a la especificación de un proceso de titulación, es claro que dicha base debe ser titulada con un ácido, y este caso, con HCl, ácido chlorhídrico, con el fin the alcanzar el punto de equivalencia.

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Consider a solution that is 1.3×10−2 M in Ba2+ and 2.0×10−2 M in Ca2+. Ksp(BaSO4)=1.07×10−10 Ksp(CaSO4)=7.10×10−5 If sodium sulf
skad [1K]

Answer:

Explanation:

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Compound of sodium carbonate and sodium bicarbonate was the name of the resulting hydrate that formed.

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