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vitfil [10]
3 years ago
7

Can the structure of an atom be broken down into smaller parts?

Chemistry
1 answer:
mel-nik [20]3 years ago
6 0

Answer

yes it can because it can be split in to neutrons and electrons.

Explanation:

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A mass spectrometer has determined the mass and abundances of all isotopes of an unknown element. The first isotope has a mass o
shepuryov [24]

Answer:

I believe it is Potassium (K)

Explanation:

I did the math on a calculator and it was the closest atomic mass to potassium.

5 0
3 years ago
A nitrde ion has 7protons,8nutrons and 10 electrons. what is the overall change
Rama09 [41]

Answer:

the overall charge on the nitride anion is  

( 3 − ) .

N power 3 − → the nitride anion

6 0
2 years ago
How is a mixture such as a plate of pasta different from a mixture such as air
stealth61 [152]

Answer:

Well there is a lot of differences between the two. Its called homogeneous and Heterogeneous mixtures. Homogeneous mixtures are all the substances are evenly distributed throughout the mixture (salt water, air, blood).  Heterogeneous mixtures are the substances that are not evenly distributed (chocolate chip cookies, pizza, rocks). So Pasta with sauce and meatballs is heterogeneous and air is homogeneous




HOPE THIS HELPS HAVE A GREAT DAY!!~

Explanation:

6 0
2 years ago
URGENT PLEASE HELP!!!
mote1985 [20]
Even though two grams seemed to disappear or vanish, the law of conversation of mass still holding true. Mercuric oxide, when heated, forms a gas of mercury and oxygen. During the investigation, some gas could have escaped or evaporated.
5 0
3 years ago
Read 2 more answers
Draw an electrolytic cell in which Mn2+ is reduced to Mn and Sn is oxidized to Sn2+. (Assume standard conditions).
babunello [35]

Answer:

-1.05 V

Explanation:

A detailed diagram of the setup as required in the question is shown in the image attached to this answer. The electrolytes chosen are SnCl2 for the anode half cell and MnCl2 for the cathode half cell. Tin rod and manganese rod are used as the anode and cathode materials respectively. Electrons flow from anode to cathode as indicated. The battery connected to the set up drives this non spontaneous electrolytic process.

Oxidation half equation;

Sn(s) ------> Sn^2+(aq) + 2e

Reduction half equation:

Mn^2+(aq) + 2e ----> Mn(s)

Cell voltage= E°cathode - E°anode

E°cathode= -1.19V

E°anode= -0.14 V

Cell voltage= -1.19 V - (-0.14V)

Cell voltage= -1.05 V

8 0
3 years ago
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