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s2008m [1.1K]
3 years ago
12

Write the name of CH3 ----CH2 ---- CH3

Chemistry
2 answers:
zavuch27 [327]3 years ago
7 0

Answer:

ORGANIC HYDROCARBON

Explanation:

kk

Olin [163]3 years ago
5 0

Answer:

PROPANE AN ORGANIC HYDROCARBON

Explanation:

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Sodium sulfide is the chemical compound with the formula Na 2 S, or more commonly its hydrate Na 2 S·9H 2 O. Both are colorless water-soluble salts that give strongly alkaline solutions. When exposed to moist air, Na 2 S and its hydrates emit hydrogen sulfide , which smells like rotten eggs.

I'm not sure if it's right but it's a guess because of the 2Na.

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A dependent variable is
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a variable (often denoted by y) whose value depends of that of another.

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3 years ago
In glycolysis, as in all the stages of cellular respiration, the transfer of electrons from electron donors to electron acceptor
Brums [2.3K]

Answer:

Oxidized,Reduced,reductant,oxidant, NAD+,NADH

Explanation:

1 when a compound donates electrons the compound becomes oxidized.such a compound is referred to as electron donor.

2 when a compound accept electron the compound becomes reduced such a compound often referred to as electron acceptor.

3 In glycolysis once the carbon containing compound that functions as electron donor is reductant.

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5 0
3 years ago
Not sure how to do this
faust18 [17]

Answer:

0.0991 M

Explanation:

Step 1: Write the neutralization reaction between oxalic acid and sodium hydroxide.

H₂C₂O₄ + 2 NaOH = Na₂C₂O₄ + 2 H₂O

Step 2: Calculate the moles of oxalic acid

The molar mass of H₂C₂O₄ is 90.03 g/mol. The moles corresponding to 153 mg (0.153 g) are:

0.153g \times \frac{1mol}{90.03g} = 1.70 \times 10^{-3} mol

Step 3: Calculate the moles of sodium hydroxide

The molar ratio of H₂C₂O₄ to NaOH is 1:2.

1.70 \times 10^{-3} molH_2C_2O_4  \times \frac{2molNaOH}{1molH_2C_2O_4} = 3.40 \times 10^{-3} molNaOH

Step 4: Calculate the molarity of sodium hydroxide

\frac{3.40 \times 10^{-3} mol}{34.3 \times 10^{-3} L} = 0.0991 M

4 0
4 years ago
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