Write the name of CH3 ----CH2 ---- CH3
2 answers:
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Explanation:
First, we will calculate fuel consumption is as follows.
= 4526 g/s
Now, we will calculate the power as follows.
Power = Fuel consumption rate × -enthalpy of combustion
=
= kW
Thus, we can conclude that maximum power (in units of kilowatts) that can be produced by this spacecraft is kW.
2,02g ------- 6,02×10²³
5,01×10⁴g --- x
N₂ + 3H₂ ⇒ 2NH₃
1mol : 3mol : 2mol
18,06×10²³ : 12,04×10²³
14,93×10²⁷ : y
5,01×10⁴g --- x
N₂ + 3H₂ ⇒ 2NH₃
1mol : 3mol : 2mol
18,06×10²³ : 12,04×10²³
14,93×10²⁷ : y