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Elan Coil [88]
2 years ago
5

what is the relationship between electron affinity and atomic radius? why do you think this relationship occurs?

Chemistry
1 answer:
tatyana61 [14]2 years ago
8 0
Electron affinity increases from left to right within a period. This is caused by the decrease in atomic radius. Electron affinity decreases from top to bottom within a group. This is caused by the increase in atomic radius.
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What is mole-to-mole stoichiometry.
borishaifa [10]

Answer:

https://youtu.be/3zmeVamEsWI

Explanation:

It is defined as the ratio of moles of one substance to the moles of another substance in a balanced equation. ... Mole ratios are the central step in performing stoichiometry because they allow us to convert moles of one substance to moles of another substance.

6 0
2 years ago
Consider a transition of the electron in the hydrogen atom from n=5 to n=9. Determine the wavelength of light that is associated
lesantik [10]
Lol i need to answer more and plus n could also = # 4.65
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3 years ago
For which of the following activities might you want to hire a chemist?
yarga [219]

examining the structure of plant cells

5 0
3 years ago
Consider the formation of [Ni(en)3]2+ from [Ni(H2O)6]2+. The stepwise ΔG∘ values at 298 K are ΔG∘1 for first step=−42.9 kJ⋅mol−1
timurjin [86]

Answer:

kf = 1.16 x 10¹⁸

Explanation:

Step 1: [Ni(H₂O)₆]²⁺  + 1en → [Ni(H₂O)₄(en)]²⁺  ΔG°1 = -42.9 kJmol⁻¹

Step 2: [Ni(H₂O)₄(en)]²⁺  + 1en → [Ni(H₂O)₂(en)₂]²⁺  ΔG°2 = -35.8 kJmol⁻¹

Step 3: [Ni(H₂O)₂(en)₂]²⁺ + 1en →  [Ni(en)₃]²⁺  ΔG°3 = -24.3 kJmol⁻¹

________________________________________________________

Overall reaction: [Ni(H₂O)₆]²⁺  + 3en → [Ni(en)₃]²⁺  ΔG°r

ΔG°r = ΔG°1 + ΔG°2 + ΔG°3

ΔG°r = -42.9 - 35.8 - 24.3

ΔG°r = -103.0 kJmol⁻¹

ΔG°r = -RTlnKf

-103,000 Jmol⁻¹ =  - 8.31 J.K⁻¹mol⁻¹ x 298 K x lnKf

kf = e ^(-103,000/-8.31x298)

kf = e ^41.59

kf = 1.16 x 10¹⁸

7 0
3 years ago
How can I calculate the mass percent of carbon, nitrogen and oxygen in caffeine, C8H10N4O2.
Ahat [919]

You must first calculate the total weight of 1 mole of the substance. You do this by finding the molar weights on the periodic table of each of the elements in the compound:

8(12.01g)+10(1.008g)+4(14.007g)+2(15.999g)=96.08g+10.08g+56.028g+31.998g=194.186g

So now we take the amount of each element that is given in the compound and divide it by the total mass of the compound:

Carbon: 96.08g

\frac{96.08g}{194.186g}= 0.49478=49.48

Carbon = 49.48%

Nitrogen: 56.028g

\frac{56.028g}{194.186g}=0.28853=28.85

Nitrogen = 28.85%

Oxygen: 31.998g

\frac{31.998g}{194.186g} =0.16478=16.48

Oxygen = 16.48%

8 0
2 years ago
Read 2 more answers
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