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Andru [333]
3 years ago
14

HELP PLEASE

Mathematics
2 answers:
madreJ [45]3 years ago
6 0

Answer:

No, because the bike order does not meet the restrictions of 4c+6a \leq 120 and 4c +4a\leq 100

Step-by-step explanation:

The correct answer is option 1:

4c+6a \leq 120 (As each child bike takes 4 hours to build and each adult bike takes 6 hours to build, and the company has building time up to 120 hours)

4c +4a\leq 100 (As each child bike takes 4 hours to test and each adult bike takes 4 hours to test, and the company has testing time up to 100 hours)

We will substitute 20 for 'c' and 6 for 'a'

4(20)+6(6) \leq 120

80+36 \leq 120

116 \leq 120

This is true.

For the second inequality;

4(20)+4(6) \leq 100

80+24 \leq 100

104 \leq 100

So, this is not true.

Hence, option 1st is true.

Alex787 [66]3 years ago
3 0
The answer that i got for your question is the first answer.
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Step-by-step explanation:

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According to the 2000 Census the population of Canton was 7,720. Holly Spring's population was 3,200. Canton's population increa
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3 years ago
Find the lengths and slopes of the diagonals to name the parallelogram. Choose the most specific name. E (-2, -4), F(0, -1), G(-
Kay [80]

Answer:

1) d) Square

2) Proofs that PWRS is a rhombus are

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Step-by-step explanation:

The given points (x, y) of the parallelogram are;

E(-2, -4), F(0, -1), G(-3, 1), H(-5, -2)

The slope, m, of the segments are found as follows;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

By computation, the slope of segment EF = 1.5

The slope of segment FG = -0.67

The slope of segment GH = 1.5

The slope of segment HE = -0.67

Therefore, EF is parallel to GH and FG is parallel to HE

The length of the sides are;

\sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

By computation, the length of segment EF = 3.61

The length of segment FG = 3.61

The length of segment GH = 3.61

The length of segment HE = 3.61

The diagonals are;

EG and FH

The length of segment EG = 5.099

The length of segment FH = 5.099

Therefore, the diagonals are equal and the parallelogram is a square

2) The given dimensions are;

P(-1, 3), Q(-2, 5), R(0, 4), S(1, 2)

A rhombus has all sides equal

The length of segment PQ = 2.24

The length of segment QR = 2.24

The length of segment RS = 2.24

The length of segment PS = 2.24

The diagonals are;

QS and PR

The length of segment QS = 4.24

The length of segment PR = 1.41

The slope of segment QR = -0.5

The slope of segment PS = -0.5

The slope of segment RS = -2

The slope of segment QP = -2

Therefore, QS≠QR the parallelogram is a rhombus

The correct option ;

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Where there are acute angles in parallelogram PQRS, then the correct option is d) Length of QR and PS is 2.2 and Length of RS and QP is 2.2

8 0
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