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uranmaximum [27]
3 years ago
7

You are driving your car and the traffic light ahead turns red.You apply the breaks for 3s and the velocity of the car decreases

to 4.5 m/s . If the cars deceleration has a magnitude of 2.7m/s^2,what is the car's displacement during this time?
Physics
1 answer:
hammer [34]3 years ago
7 0

Answer:

The car's displacement during this time is 25.65 meters.

Explanation:

Given that,

Final velocity of the car, v = 4.5 m/s

Deceleration of the car, a=-2.7\ m/s^2

Let u is the initial speed of the car. It is given by :

v=u+at

u=v-at

u=4.5-(-2.7)\times 3

u = 12.6 m/s

Let d is the car's displacement during this time. It can be calculated using second equation of motion as :

d=ut+\dfrac{1}{2}at^2

d=12.6\times 3+\dfrac{1}{2}\times (-2.7)\times 3^2

d = 25.65 meters

So, the car's displacement during this time is 25.65 meters. Hence, this is the required solution.                        

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A thin spherical spherical shell of radius R which carried a uniform surface charge density σ. Write an expression for the volum
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Explanation:

From the given information:

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To verify the units:

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↓         ↓            ↓

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