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uranmaximum [27]
3 years ago
7

You are driving your car and the traffic light ahead turns red.You apply the breaks for 3s and the velocity of the car decreases

to 4.5 m/s . If the cars deceleration has a magnitude of 2.7m/s^2,what is the car's displacement during this time?
Physics
1 answer:
hammer [34]3 years ago
7 0

Answer:

The car's displacement during this time is 25.65 meters.

Explanation:

Given that,

Final velocity of the car, v = 4.5 m/s

Deceleration of the car, a=-2.7\ m/s^2

Let u is the initial speed of the car. It is given by :

v=u+at

u=v-at

u=4.5-(-2.7)\times 3

u = 12.6 m/s

Let d is the car's displacement during this time. It can be calculated using second equation of motion as :

d=ut+\dfrac{1}{2}at^2

d=12.6\times 3+\dfrac{1}{2}\times (-2.7)\times 3^2

d = 25.65 meters

So, the car's displacement during this time is 25.65 meters. Hence, this is the required solution.                        

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edward travels 150 kilometers due west and then 200 kilometers in a direction 60 degrees north of west.what is his displacement
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The displacement of Edward in the westerly direction is determined as 338.32 km.

<h3>What is displacement of Edward?</h3>

The displacement of Edward can be determined from different methods of vector addition. The method applied here is triangular method.

The angle between the 200 km north west and 150 km west = 60 + 90 = 150⁰

The displacement is the side of the triangle facing 150⁰ = R

R² = a² + b² - 2abcosR

R² = 150² + 200²  - (2x 150 x 200)xcos(150)

R² = 62,500 - (-51,961.52)

R² = 114,461.52

R = 338.32 km

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