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3 years ago

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How many grams of N2 are required to react with 2.30 moles of Mg in the following process? 3 Mg + N2 → Mg3N2? (Mg = 24.3 g/mol,

N = 14.0 g/mol)

1 answer:

aivan3 [116]3 years ago

5 0

Answer: 10.73 g

Explanation:

2.3 mol Mg * (1 mol N2 / 3 mol Mg) * (14 g Mg / 1 mol g) = 10.73

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What is the pH of a 0.100 M HI solution? Is that neutral, acidic, or basic? acidic What is the pOH of a 0.100 M HI solution? Is

inessss [21]

<u>Answer:</u> The pH and pOH of the solution is 1 and 13 respectively and the solution is acidic in nature.

<u>Explanation:</u>

There are three types of solution: acidic, basic and neutral

To determine the type of solution, we look at the pH values.

The pH range of acidic solution is 0 to 6.9
The pH range of basic solution is 7.1 to 14
The pH of neutral solution is 7.

We are given:

Concentration of HI = 0.100 M

1 mole of HI produces 1 mole of hydrogen ions and 1 mole of iodide ions

To calculate the pH of the solution, we use the equation:

$pH=-\log[H^+]$

We are given:

$[H^+]=0.100M$

Putting values in above equation, we get:

$pH=-\log(0.100)\\\\pH=1$

To calculate the pOH of the solution, we use the equation:

pH + pOH = 14

$pOH=14-1=13$

Hence, the pH and pOH of the solution is 1 and 13 respectively and the solution is acidic in nature.

4 0

3 years ago

A chemical equation is shown: C2H4 + O2 → CO2 + H2O According to the law of conservation of mass, how many atoms of oxygen exist

astraxan [27]

Answer:

6 oxygens on the product side

Explanation:

1) balance the equation:

C2H4 + 3O2 → 2CO2 + 2H2O

2) calculate the number of oxygens on the product side

2CO2=4

2H2O=2

6 0

3 years ago

Which of the following 0.820 M solutions would have the greatest colligative effect?

eimsori [14]

Answer:

K3PO4

Explanation:

Recall that colligative properties depends on the number of particles present. The greater the number of particles present, the greater the degree of colligative properties of the solution. Let us look at each option individually;

SrCr2O7-------> Sr^2+ + Cr2O7^2- ( 2 particles)

C4H11N (not ionic in nature hence it can not dissociate into ions)

K3PO4-------> 3K^+ + PO4^3- (4 particles)

Rb2CO3-------> 2Rb^+ + CO3^2- (3 particles)

Hence K3PO4 has the greatest number of particles and will display the greatest colligative effect.

8 0

3 years ago

A flexible container at an initial volume of 6.13 L contains 2.51 mol of gas. More gas is then added to the container until it r

aleksley [76]

Answer:

2.12 moles of gas were added.

Explanation:

We can solve this problem by using<em> Avogadro's law</em>, which states that at constant temperature and pressure:

V₁n₂=V₂n₁

Where in this case:

V₁ = 6.13 L

n₂ = ?

V₂ = 11.3 L

n₁ = 2.51 mol

We <u>input the data</u>:

6.13 L * n₂ = 11.3 L * 2.51 mol

n₂ = 4.63

As <em>4.63 moles is the final number of moles</em>, the number of moles added is:

4.63 - 2.51 = 2.12 moles

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Kruka [31]

Lipid you can look up the chemical structures and lipids are the longest which make them the largest

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