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pashok25 [27]
2 years ago
8

Hi can someone please help me!

Chemistry
1 answer:
Ratling [72]2 years ago
7 0

Answer:

a) 2

b) 2

c) 5

d) 5

e) 5

Explanation:

a) There is 1 Ag atom and 1 Cl atom. <em>When there's no subscript number next to an element, it means there is only one.</em>

b) There is 1 Ca atom and 1 O atom.

c) There are 3 Mg atoms (there's a subscript 3 next to Mg) and 2 N atoms.

d) There are 2 Al atoms and 3 O atoms.

e) There are 2 Sc atoms and 3 S atoms.

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True or false? Covalent molecules are formed when non-metal atoms share electrons with other non-metal atoms.
Tomtit [17]

Answer:

true

covalent bonds are between non metals and nonmetals. and they are sharing electrons.

7 0
3 years ago
If f is a reactive nonmetal, which other element or elements shown here do you expect to also be a reactive nonmetal?
vichka [17]
You did not include the list but F is fluorine. The first halogen.

So, you can expect that the other members of the same group (halogens, column 17 of the periodic table) exhibit similar chemical behavior (reactivity).

So, I am sure your list contains one or more of theses elements: Cl (chlorine), Br (bromine), and I (iodine).

All of them you can expect to also be reactive non metal.
3 0
3 years ago
Using the balanced chemical reaction below, how many grams of copper (cu) metal can be obtained from 1.00 kg of copper ore (cu3f
aleksklad [387]

Answer : Mass of copper (Cu) metal obtained = 556.281 g

Solution : Given,

Mass of copper ore = 1 Kg = 1000 g

From the periodic table, the molar mass of copper and copper ore are

Molar mass of copper = 63.546 g/mole

Molar mass of copper ore, Cu_{3}FeS_{3} = 342.678 g/mole

First we have to calculate the number of moles of copper ore, Cu_{3}FeS_{3}

Moles of  Cu_{3}FeS_{3} = \frac{\text{ Mass of copper ore}}{\text{ Molar mass of copper ore}} = \frac{1000g}{342.678g/mole} = 2.918 moles

The balanced chemical reaction is :

2Cu_{3} FeS_{3}(s)+7O_{2}(g)\rightarrow 6Cu(s)+2FeO(s)+6SO_{2}(g)

From this chemical reaction, we conclude that

2 moles of Cu_{3}FeS_{3} gives          →     6 moles of Cu

2.918 moles of Cu_{3}FeS_{3} gives   →      \frac{6moles}{2moles}\times 2.918moles

                                                           = 8.754 moles

Thus, the Moles of copper (Cu) = 8.754 moles

Now, calculate the Mass of copper (Cu).

Mass of copper (Cu) = Moles of copper (Cu) × Molar mass of copper (Cu)

                                  = 8.757 moles × 63.546 g/moles

                                  = 556.281 g                                

4 0
3 years ago
Read 2 more answers
What is the concentration of a solution when 50.0 mL of 0.436 M NH ₄NO ₃ is diluted to a new volume of 250.0 mL
Blababa [14]

Answer:

0.0872 M

Explanation:

Use the equation M1V1 = M2V2

0.436(50.0) = (x)(250.0)

21.8 = 250x

0.0872 = x

3 0
3 years ago
What are the answers to these?
r-ruslan [8.4K]

Answer:

Answer at the bottom

Explanation:

A Be

B Li

C Mg

D Nahe answered their bottom

8 0
2 years ago
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