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3 years ago

Why is rain water always somewhat acidic?

2 answers:

8 0

Answer: a. Because the carbon dioxide in the air mixes with it to form carbonic acid and d. Because sulfur dioxide released from burning petroleum mixes with it to form sulfuric acid.

Explanation:

$CO_2+H_2O\rightarrow H_2CO_3$

$SO_2+H_2O\rightarrow H_2SO_3$ , which oxides in air to form $H_2SO_4$

Thus carbonic acid $H_2CO_3$ and sulphuric acid $H_2SO_4$ mixes with rain to form acid rain.

Nitrogen monoxide $NO$ and not nitrous oxide $N_2O$ forms nitric acid.

Olin [163]3 years ago

3 0

A.Because the Carbon dioxide in the air mixes it to form carbonic acid

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What is the mole fraction?

sleet_krkn [62]

Mole fraction is a unit of concentration, defined to be equal to the number of moles of a component divided by the total number of moles of a solution. Because it is a ratio, mole fraction is a unitless expression. The mole fraction of all components of a solution, when added together, will equal 1.

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4 years ago

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GuDViN [60]

The answer is the second one

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3 years ago

Manganese atom has 30 neutrons and atomic number 25

Liono4ka [1.6K]

Answer:

The most common oxidation states of manganese are 2+, 3+, 4+, 6+, and 7+.

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3 years ago

A student named a particular compound 2-ethyl-3-methyl-2-butene. Assuming that the student's choice actually corresponded to the

Likurg_2 [28]

Answer:

2-ethyl-3-methylbut-2-ene

Explanation:

The whole idea of IUPAC nomenclature is to devise a universally accepted system of writing the name of a compound from its structure.

According to IUPAC nomenclature, the root of the compound is the longest carbon chain. The substituents are named in alphabetical order and in such a way as to give each one the lowest number. The position of the functional group is indicated accordingly.

For the compound in question, its correct IUPAC name is 2-ethyl-3-methylbut-2-ene.

4 0

3 years ago

I'll mark like brainliest please

Ilya [14]

Answer:

A. 1.75mol of CO2

B. 120g of urea

C. 72g of water

Explanation:

The balanced equation for the reaction is given below:

CO2+ 2NH3 --> H2NCONH2 + H2O

A. From the balanced equation,

1mole of CO2 requires 2moles of NH3.

Therefore, Xmol of CO2 will require 3.5moles of NH3 ie

Xmol of CO2 = 3.5/2 = 1.75mol

B. Let us calculate their molar mass

MM of H2NCONH2 = (2x1)+14+12+16+14+(2x1) = 60g/mol

MM of NH3 = 14 +(3x1) = 17g/mol

But from the balanced equation, 2 moles of NH3 was required. Therefore the mass conc. of NH3 = 2 x 17 = 34g.

Now we calculate the mass of urea produced as follows:

From the equation,

34g of NH3 was required to produce 60g of urea.

Therefore, 68g of NH3 will produce Xg of urea i.e

Xg of urea = (68x60)/34 = 120g

C. From the balanced equation,

2moles of NH3 was required to produced 1mole of H2O.

Therefore, 8 moles of NH3 will produce Xmol of water ie

Xmol of H2O = 8/2 = 4moles

Converting this mole(4moles of water to grams), we have:

MM of H2O = (2x1)+ 16 = 18g/mol

Mass conc. of H20 = 4 x 18 = 72g

6 0

4 years ago