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Bond [772]
2 years ago
6

What causes a roller coaster to "lose" energy and stop? What force does it lose energy to? Give a detailed explanation that is e

asy to understand.
Physics
1 answer:
Zarrin [17]2 years ago
5 0

Roller coasters work by utilizing its potential energy. Potential energy is "lost" as the cars lose height, subsequently gaining kinetic energy as revealed by increased speeds (and loop the loop). As the cars of the roller coaster course through the changing heights, it constantly swaps between potential and kinetic energy. Theoretically, this process could be endless. However, energy is continually "lost" because of dissipative forces such as friction and air resistance.

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) a 1.0 kilogram laboratory cart moving with a velocity of 0.50 meter per second due east collides with and sticks to a similar
ZanzabumX [31]
Momentum would be the same before and after the collision
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create a formula giving the strength of the induced field (B) i terms of current (I) and the distance from the wire to the probe
iren [92.7K]
So we need to find the formula for magnetic field B using the current (I) and the distance from the probe (d). So, We know that the stronger the current I, the stronger the magnetic field B. That tells us that the I and B are proportional. Also we know that the strength of the magnetic field B is weaker as the distance d of the probe increases. That tells us that B and d are inversely proportional. So our formula should have B=(I/d)*c where c is a constant of proportionality. c=μ₀/2π where μ₀ is the permeability of free space. So finally our formula is B=(μ₀I)/(2πd). 
6 0
2 years ago
What is the deceleration of the rocket sled if it comes to rest in 1.1 s from a speed of 1000 km/h? (such deceleration caused on
Wewaii [24]

The deceleration of the rocket sled if it comes to rest in 1.1 s from a speed of 1000 km/h is  252.52\ m/s^2.

The acceleration in opposite direction is known as the deceleration. Basically the deceleration is negative value of the acceleration since the negative sign depicts its opposite in direction.

The given data:

time, t = 1.1 s

initial speed, u = 1000 km/h = \frac{2500}{9}\ m/s

final speed, v = 0 m/s

So we will be using the equation of motion, that is,

v = u + at

\therefore 0=\frac{2500}{9} + a(1.1)

\Rightarrow a=-\frac{2500}{9(1.1)}

\therefore a = - 252.52 \ m/s^2

Hence , the deceleration of the rocket is  252.52\ m/s^2.

To learn more about Attention here:

brainly.com/question/28500124

#SPJ4

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1 year ago
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