Answer:
a).11.546J
b).2.957kW
Explanation:
Using Inertia and tangential velocity
a).
![w=2250*2\pi *\frac{1}{60}\\ w=235.61](https://tex.z-dn.net/?f=w%3D2250%2A2%5Cpi%20%2A%5Cfrac%7B1%7D%7B60%7D%5C%5C%20w%3D235.61)
![I=\frac{1}{2}*m*((\frac{d_{i} }{2})^{2} +(\frac{d_{e} }{2})^{2})\\m=100g *\frac{ikg}{1000g}=0.1kg\\ d_{i}=3cm*\frac{1m}{100cm}=0.03m \\ d_{e}=18cm*\frac{1m}{100cm}=0.18m\\I=\frac{1}{2}*0.1kg*((\frac{0.03m}{2})^{2} +(\frac{0.18m}{2})^{2})\\I=0.41625x10^{-3}kg*m^{2}](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B1%7D%7B2%7D%2Am%2A%28%28%5Cfrac%7Bd_%7Bi%7D%20%7D%7B2%7D%29%5E%7B2%7D%20%2B%28%5Cfrac%7Bd_%7Be%7D%20%7D%7B2%7D%29%5E%7B2%7D%29%5C%5Cm%3D100g%20%2A%5Cfrac%7Bikg%7D%7B1000g%7D%3D0.1kg%5C%5C%20d_%7Bi%7D%3D3cm%2A%5Cfrac%7B1m%7D%7B100cm%7D%3D0.03m%20%5C%5C%20d_%7Be%7D%3D18cm%2A%5Cfrac%7B1m%7D%7B100cm%7D%3D0.18m%5C%5CI%3D%5Cfrac%7B1%7D%7B2%7D%2A0.1kg%2A%28%28%5Cfrac%7B0.03m%7D%7B2%7D%29%5E%7B2%7D%20%2B%28%5Cfrac%7B0.18m%7D%7B2%7D%29%5E%7B2%7D%29%5C%5CI%3D0.41625x10%5E%7B-3%7Dkg%2Am%5E%7B2%7D)
Now using Inertia an w
![E=\frac{1}{2}*I*(w)^{2} \\ E=\frac{1}{2}*0.416x10^{-3}*(235.61)^{2} \\E=11.54J](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B1%7D%7B2%7D%2AI%2A%28w%29%5E%7B2%7D%20%5C%5C%20E%3D%5Cfrac%7B1%7D%7B2%7D%2A0.416x10%5E%7B-3%7D%2A%28235.61%29%5E%7B2%7D%20%5C%5CE%3D11.54J)
average power=![\frac{11.4J}{0.230s}=50.2 W](https://tex.z-dn.net/?f=%5Cfrac%7B11.4J%7D%7B0.230s%7D%3D50.2%20W)
b).
power=t*w
P=![11.5465*0.25*235.61](https://tex.z-dn.net/?f=11.5465%2A0.25%2A235.61)
P=2.957 kW
Answer:
The force applied is 32 N
Explanation:
F = ma
F = 8 × 4
F = 32 N
Answer:
The wavelength of the light is
.
Explanation:
Given that,
Distance between the slit centers d= 1.2 mm
Distance between constructive fringes ![\beta= 0.3\ cm](https://tex.z-dn.net/?f=%5Cbeta%3D%200.3%5C%20cm)
Distance between fringe and screen D= 5 m
We need to calculate the wavelength
Using formula of width
![\beta=\dfrac{D\lambda}{d}](https://tex.z-dn.net/?f=%5Cbeta%3D%5Cdfrac%7BD%5Clambda%7D%7Bd%7D)
Put the value into the formula
![0.3\times10^{-2}=\dfrac{5\times\lambda}{1.2\times10^{-3}}](https://tex.z-dn.net/?f=0.3%5Ctimes10%5E%7B-2%7D%3D%5Cdfrac%7B5%5Ctimes%5Clambda%7D%7B1.2%5Ctimes10%5E%7B-3%7D%7D)
![\lambda=\dfrac{0.3\times10^{-2}\times1.2\times10^{-3}}{5}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7B0.3%5Ctimes10%5E%7B-2%7D%5Ctimes1.2%5Ctimes10%5E%7B-3%7D%7D%7B5%7D)
![\lambda=7.2\times10^{-7}\ m](https://tex.z-dn.net/?f=%5Clambda%3D7.2%5Ctimes10%5E%7B-7%7D%5C%20m)
![\lambda=7200\ \AA](https://tex.z-dn.net/?f=%5Clambda%3D7200%5C%20%5CAA)
Hence, The wavelength of the light is
.
Answer:
Selenium dichloride
Explanation:
Selenium (Se) and Chlorine (Cl) are both elements capable of combining together to form a compound with the chemical formula; SeCl2. Since the chlorine atom is more electronegative than selenium atom, the chlorine pulls more electrons towards itself to form an IONIC bond.
The SeCl2 compound formed is called Selenium dichloride as two atoms of Chlorine are needed to combine with one atom of Selenium to form the compound.
1.8 is the mechanical advantage of the lever.
<h3>Definition of mechanical advantage</h3>
The theoretical mechanical advantage of a system is the ratio of the force that performs the useful work to the force applied, assuming there is no friction in the system.
The advantage gained by the use of a mechanism in transmitting force specifically the ratio of the force that performs the useful work of a machine to the force that is applied to the machine.
Mechanical advantage is given by the ratio of the load lifted to the force applied to lift the load.
In this case, Mechanical advantage=L/E where L is the load and E is the effort applied.
Mechanical advantage= 90/50 =1.8
Question-you use a lever to lift a heavy tree branch. you apply a force of 50 n and the lever lifts the branch with a force of 90 n. what is the mechanical advantage of the lever?
To learn more about the Mechanical advantage visit the link
brainly.com/question/16617083
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