Complete Question:
Suppose that an asteroid traveling straight toward the center of the earth were to collide with our planet at the equator and bury itself just below the surface. What would have to be the mass of this asteroid, in terms of the earth’s mass M, for the day to become 25.0% longer than it presently is as a result of the collision? Assume that the asteroid is very small compared to the earth and that the earth is uniform throughout.
Answer:
m = 0.001 M
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<u><em>Kinetic Energy Pulls Any object to the ground.This Energy is a part of Gravity.</em></u>
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Answer:
Basic kinematics, negating drag and assuming ideal conditions, we use the equation:
d=vi*t+1/2*a*t^2
Since vi is 0 (we know this because you’re dropping it, not throwing it)…
…and the only acceleration acting on it is gravity, a=9.8 m/s^2…
…we get
d=1/2(9.8)(5)^2
Explanation:
Some quick mental math tells us that this is about 125 m.
Plugging it in, we find it to be 122.5 m.
