So mathematical harmonics are based around a divergent set of fractions. Sigma(1/n)
with the 1st harmonic being... well 1, or 1 full wavelength.The second harmonic is exactly 1/2 the wavelength of the 1st with the third being 1/3 the wavelength. As Wavelengths go down, frequencies go up in a perfect ratio.
Second Harmonic has double the Frequency of the 1st or base note. Third Harmonic is triple and so on.
So the Harmonic set of 375 is.
1. 375
2. 375×2=750
3. 375×3= 1125
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etc (: I hope this helps.
Answer:
The offspring is homozygous for eye color.
Explanation:
Brown eyes is the shared allele of both parents (meaning homozygous) and an allele for hair type was not inherited from only one parents but from both however will recieve the dominant trait. (This is my best guess; I haven't studied this in awhile though)
Answer:
Explanation:
Given
Initial velocity u = 200m/s
Final velocity = 4m/s
Distance S = 4000m
Required
Acceleration
Substitute the given parameters into the formula
v² = u²+2as
4² = 200²+2a(4000)
16 = 40000+8000a
8000a = 16-40000
8000a = -39,984
a = - 39,984/8000
a = -4.998m/s²
Hence the acceleration is -4.998m/s²
<span>It reacts to the </span>motion<span>. If the mass hanging from the pulley was overwhelmingly heavier than the mass on the ramp, it'll obviously pull the ramp mass up and thus </span>friction<span> would be trying to oppose this and vice versa. </span>
Answer:

and

Explanation:
Given:
- first charge,

- second charge,

- position of first charge,

- position of second charge,

Now since there are only 2 charges and of the same sign so they repel each other. This repulsion will be zero at some point on the line joining the charges.
<u>Now, according to the condition, electric field will be zero where the effects of field due to both the charges is equal.</u>

- since first charge is greater than the second charge so we may get a point to the right of the second charge and the distance between the two charges is 1 meter.





Since we have assumed that the we may get a point to the right of second charge so we calculate with respect to the origin.

and
