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3 years ago

How are scientists able to measure the age of earth?

Physics

1 answer:

RoseWind [281]3 years ago

4 0

Explanation:

Through the uranium-lead dating, you can establish the age of rocks that formed from 1 million years ago to 4.5 billion years with enough precision. Dating meteorites using this method, It is possible to establish the age of the earth, since these are pieces that are present since the formation of the solar system, so they are approximately the same age as the Earth.

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At 8:00 am, the temperature in the earth science room was measured to be 62 degrees Fahrenheit. By 12:00 pm, the temperature had

mash [69]

Rate of change = (amount of change) / (time for the change)

Amount of change = (temp at the end) minus (temp at the beginning)

Amount of change = (70°F) minus (62°F) = 8°F

Time for the change = (time at the end) minus (time at the beginning)

Time for the change = (1200 - 0800) = 4 hours

Rate of change = (8°F) / (4 hours)

Rate of change = 2°F per hour

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3 years ago

A/An _____________ ( wind vane / anemometer ) can be used to measure wind speed.

Wewaii [24]

Answer:

The answer is an anemometer

Explanation:

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3 years ago

An 877 kg drag race car accelerates from rest to 116 km/h in 0.951 s. What change in momentum does the force produce? Answer in

Eduardwww [97]

Answer:

The change in momentum is 28265.71 kg-m/s.

Explanation:

Given that,

Mass of a car, m = 877 kg

Initial velocity of the car, u = 0 (at rest)

Final velocity of the car, v = 116 km/h = 32.23 m/s

Time, t = 0.951 s

We need to find the change in momentum produced by the force. It can be calculated as the difference of final momentum and the initial momentum.

$\Delta P=m(v-u)\\\\=877\times (32.23-0)\\\\=28265.71\ kg-m/s$

So, the change in momentum is 28265.71 kg-m/s.

7 0

2 years ago

Guys help...A spring that obeys Hooke's law, with a spring constant k1, is cut into N identical springs, each with a spring cons

Tems11 [23]

Answer:

K2 = N*K1

Explanation:

The force you apply to each section is the same you apply to the whole spring, but the extension of each section is dX/N (if dX is the extension of the entire spring)

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3 years ago

Solving elastic collisions problem the hard way

vova2212 [387]

Answer:

<h2>Solving elastic collisions problem the hard way</h2><h3 />

Explanation:

perfect drawing

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3 years ago