Answer:
4.8 %
Explanation:
We are asked the concentration in % by mass, given the molarity of the solution and its density.
0.8 molar solution means that we have 0.80 moles of acetic acid in 1 liter of solution. If we convert the moles of acetic acid to grams, and the 1 liter solution to grams, since we are given the density of solution, we will have the values necessary to calculate the % by mass:
MW acetic acid = 60.0 g/mol
mass acetic acid (the solute) = 0.80 mol x 60 g / mol = 48.00 g
mass of solution = 1000 cm³ x 1.010 g/ cm³ (1l= 1000 cm³)
= 1010 g
% (by mass) = 48.00 g/ 1010 g x 100 = 4.8 %
Answer : The volume of water added are, 15 mL
Explanation :
Formula used :
where,
are the initial molarity and volume of HCl.
are the final molarity and volume of water.
We are given:
Putting values in above equation, we get:
Hence, the volume of water added are, 15 mL
D. Biased data is likely skewed for or against some variable tested, meaning it isn't an honest study.
