Answer:
The molarity of the acid HX is 6.0 M.
Explanation:
We determine the amount of moles of KOH used to neutralize the acid:
=0.12 moles KOH
Then, we calculate the amount of moles of acid:
0.12 moles KOH×=0.12 moles HX
The molarity of HX is:
=6.0 M
Explanation:
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Answer:
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<span>the reactants and products are different substances
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