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Lelu [443]
3 years ago
5

Magnesium bromide is prepared in a laboratory using the reaction below. Typically, the magnesium bromide is recoveted as a solid

by heating way the remaining water
Mg(s) + 2 HB-(aq) - MgBrac) + H200)
If 0.940 mole of HBr in solution is added to 16.5 grams of Mgo in a beaker and then is heated until dry, what are the expected contents of the beaker?
Chemistry
1 answer:
Amiraneli [1.4K]3 years ago
6 0
Can you give more examples?
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A copper cylinder, 12.0 cm in radius, is 44.0 cm long. If the density of commoner is 8.90 g/cm3, calculate the mass in grams of
inna [77]

The mass of the copper cylinder is 177065.856g

Given:

Radius of the copper cylinder R=12cm

Height of the copper cylinder H=44cm

Density of the cylinder=8.90 \frac{g}{c m^{3}}

To find:

Mass of the copper cylinder

<u>Step by Step by explanation:</u>

Solution:

According to the formula, Mass can be calculated as

\rho=\frac{m}{v} and from this

m=\rho \times v

Where, m=mass of the cylinder

\rho =density of the cylinder

v=volume of the cylinder

And also cylinder is provided with radius and height value.

So volume of the cylinder is calculated as

v=\pi r^{2} h

Where \pi=3.14

r=radius of the cylinder=12cm

h=height of the cylinder=44cm

Thus, v=3.14 \times 12^{2} \times 44

v=3.14 \times 144 \times 44

v=19895.04 \mathrm{cm}^{3}

And we know that, m=\rho \times v

Substitute the known values in the above equation we get

m=8.90 \times 19895.04  

m=177065.856g or 177.065kg

Result:

Thus the mass of the copper cylinder is 177065.856g

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