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3 years ago

Aqueous solutions of lithium sulfate and calcium nitrate are mixed, forming the precipitate

Chemistry

1 answer:

Mashcka [7]3 years ago

4 0

Answer:

(aq) Li2SO4 + (aq) Ca(NO3)2 --> (s) CaSO4 + (aq) 2LiNO3

Explanation:

Aqueous Lithium Sulfate is Li2SO4

Aqueous Calcium Nitrate is Ca(NO3)2

When they're mixed, we get the double displacement solution Calcium Sulfate and Lithium Nitrate.

Precipitate is solid.

We got solid Calcium Sulfate so the other solution must be aqueous.

CaSO4 (s) --> Calcium Sulfate product

LiNO3 (aq) --> Lithium Nitrate product

We balance equation now. 2 Lithiums total and 2 Nitrates total. (Cuz there are 2 on the other side, 1 here)

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4 years ago

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3 years ago

Considering that the mantle is 44.8% oxygen and 21.5% silicon by mass, calculate the mole ratio of oxygen atoms to silicon atoms

horrorfan [7]

The mantle has a mass of around $4.278 X 10 ^2^4 kg$ that is around 68.4% of earth's mass.

So to calculate moles we need to first find out the mass of oxygen and silicon present in mantle. It is given that oxygen is 44.8% by mass in mantle and 21.5% by mass in mantle, therefore to calculate its mass, we need to use $\text{mass percentage }=\frac{\text{mole of solute}}{\text{mass of solution}}\times100$

Now, to calculate mass percentage of oxygen

$44.8 =\frac{x}{4.278X10^2^4kg}\times100$

$x= 191.65\times10^2^2kg$

Similarly the mass of silicon can be calculated

$21.5 =\frac{x}{4.278X10^2^4kg}\times100$

$x=91.977\times10^2^2kg$

Now, the moles of any substance is calculated by

$\text{moles}= \frac{\text{given mass}}{\text{molar mass}}$

$\text{moles of oxygen}= \frac{191.65\times10^2^2kg}{2.6566962\times10^-^2^6kg}$

where, mass of oxygen in kilograms is $2.6566962\times10^-^2^6kg$

So, $\text{moles of oxygen}=72.1384\times10^4^8\text{moles of O}$

Similarly $\text{moles of silicon}= \frac{91.977\times10^2^2kg}{4.663\times10^-^2^6kg}$

$\text{moles of silicon}=19.724\times10^4^8\text{moles of Si}$

Now, to calculate mole ratio we need to divide every moles to the lowest calculated mole that is the moles of Si and round it off to the nearest whole number.

$\text{mole ratio of oxygen}= \frac{72.138\times10^4^8kg}{19.724\times10^4^8kg}$