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maxonik [38]
4 years ago
14

What is an alpha particle?

Chemistry
2 answers:
kolezko [41]4 years ago
6 0

Answer:

D. A particle consisting of two protons and two neutrons

Explanation:

I took the test and got it correct also hi everyone from FLVS!

alina1380 [7]4 years ago
5 0
An alpha particle is a particle consisting of two protons and two neutrons. (Third option)


I hope this helped! c:

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A sample of fluorine gas exerts a pressure of 900 mmHg. When the pressure is changed to 1140 mmHg, the volume is 250 mL. What wa
UNO [17]
Let's use Boyle's Law here. P1*V1 = P2*V2
Given: (assuming that there are decimals at the end for Sig Figs)
P1 = 900.mmHg
P2 = 1140.mmHg
V1 = ???
V2 = 250.mL

900.mmHg* ??? = 1140.mmHg * 250.mL
??? = 1.27*250.mL
??? = 318.mL

Therefore, the original volume is 318mL.
8 0
3 years ago
Which is a cause of polarity in water molecules? partial negative charge on the hydrogen atoms partial positive charge on the ox
Bumek [7]

Answer:

high electronegativity difference between oxygen and hydrogen

Explanation:

The electronegativity value of O and H are 3.5 and 2.1 respectively. The electronegativity difference of the O-H bond in H₂O is 1.4.  

  • When the elctronegativity difference between two atoms in bond is below 0.5 the bond is nonpolar covalent.  
  • When the elctronegativity difference between two atoms in bond is between 0.5 and 2.0 the bond is polar covalent.  
  • When the elctronegativity difference between two atoms in bond is above 0.5 the bond is ionic.  

Thus the O-H is a polar covalent bond. This explains the polarity in water molecules.

8 0
4 years ago
Read 2 more answers
List the following compounds in decreasing electronegativity difference. cl2 hcl nacl
Mkey [24]
Based on Pauling Scale, electro negativity of Cl = 3.2, Na = 0.9 and H = 2.1

Thus, Electronegativity difference  in Cl_{2} = 3.2 -3.2 = 0
Electronegativity difference  in NaCl = 3.2-0.9 = 2.3
Similarly, Electronegativity difference  in HCl = 3.2 - 2.1 = 1.1

Thus, among the listed molecules following is the decreasing order of electronegativity difference: NaCl> HCl > Cl_{2}
8 0
3 years ago
The ΔG°f of atomic oxygen is 230.1 kJ/mol. Find ΔG° for the following dissociation reactionO2 (g) <--> 2O (g)then calculat
marusya05 [52]

Answer:

Kc = 2.145 × 10⁻⁸¹

Explanation:

Let's consider the following reaction:

O₂(g) ⇄ 2O(g)

The standard Gibbs free energy for the reaction (ΔG°) can be calculated using the following expression:

ΔG° = Σnp. ΔG°f(p) - Σnp. ΔG°f(p)

where,

ni are the moles of products and reactants

ΔG°f(p) are the standard Gibbs free energy of formation of products and reactants

In this case,

ΔG° = 2 × ΔG°f(O) - 1 × ΔG°f(O₂)

ΔG° = 2 × 230.1 kJ/mol - 1 × 0 kJ/mol

ΔG° = 460.2 kJ/mol

With this information, we can calculate the equilibrium constant (Kc) using the following expression:

Kc=e^{-\Delta G \°/R.T } = e^{-460.2 kJ/mol/(8.314 \times 10^{-3}kJ/mol.K)  \times 298K }=2.145 \times 10^{-81}

3 0
3 years ago
Which picture above represents a mixture?<br> A<br> B<br> C
Mandarinka [93]

Answer:

b

Explanation:

because the others are compound and element

brainlllist plz

8 0
3 years ago
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