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stellarik [79]
3 years ago
14

For the molecular compound dioxygen difluoride , what would you multiply "grams of O2F2 " by to get the units "molecules of O2F2

"
Chemistry
1 answer:
Aloiza [94]3 years ago
7 0

Answer:

Molecules of O₂F₂ = mass of O₂F₂ × (1 mole O₂F₂ / 70 g O₂F₂) × (6.02 × 10²³ molecules / one mole of O₂F₂)

Explanation:

The Avogadros constant gives the the number of specified entities in one mole of a substance. One mole of any substance contains 6.02 × 10²³ particles. Therefore, one mole of O₂F₂ contains 6.02 × 10²³ molecules.

Also, the molar mass of a substance is the mass in grams of one mole of that substance. It is obtained by summing the relative atomic masses of all the atoms of the elements in the substance. For O₂F₂, the molar mass = (2 × 16 + 2 × 19) g/mol = 70 g/mol

Converting to molecules of O₂F₂;

To convert from grams of a substance to molecules of that substance, multiply by the ratio of one mole and mass of one mole, and then by the number of molecules per mole.

Molecules of A = mass of A × (1 mole / mass of one mole) × (6.02 × 10²³ molecules / 1 mole)

Therefore,Molecules of O₂F₂ = mass of O₂F₂ × (1 mole O₂F₂ / 70 g O₂F₂) × (6.02 × 10²³ molecules /one mole of O₂F₂)

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If you have an aqueous solution that contains 1.5 moles of HCl, how many moles of ions are in the solution?
Citrus2011 [14]
There will be three moles of ions.
Because in an aqueous solution, HCl will break apart into  <span>H<span>+ and Cl- ions. 
</span></span>HCl -> <span>H+</span><span> + </span><span>C<span>l<span>−
</span></span></span>1.5 HCl -> 1.5 H+ + 1.5 Cl−<span>
So the aqueous solution will have 1.5 moles of hydrated hydrogen ions and 1.5 moles of hydrated chloride ions. So, a total of 3 moles of ions are present in the aqueous solution of 1.5 moles of HCl. </span>
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3 years ago
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A chemist prepares a solution of ironIII chloride FeCl3 by measuring out 72.7mg of FeCl3 into a 100.mL volumetric flask and fill
dalvyx [7]

<u>Answer:</u> The molarity of chloride anions in the solution is 0.01344 M

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Given mass of ferric chloride = 72.7 mg = 0.0727 g    (Conversion factor:  1 g = 1000 mg)

Molar mass of ferric chloride = 162.2 g/mol

Volume of solution = 100 mL

Putting values in above equation, we get:

\text{Molarity of solution}=\frac{0.0727\times 1000}{162.2\times 100}\\\\\text{Molarity of solution}=0.00448M

1 mole of ferric chloride contains 1 mole of Fe^{3+} ions and 3 moles of Cl^- ions

Moles of Cl^- = (3 × 0.00448) = 0.01344 M

Hence, the molarity of chloride anions in the solution is 0.01344 M

3 0
3 years ago
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