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Advocard [28]
3 years ago
5

In a nuclear power plant, the nuclear reaction is kept from going critical by keeping the rate of reaction safe. How do the cont

rol rods figure into this?
A. The controls rods absorb the excess heat produced in the reaction.
B. The controls rods absorb excess neutrons, keeping them from causing too many uranium atoms to split too quickly.
C. The control rods provide additional neutrons to keep the reaction going.
D. The control rods absorb excess uranium atoms so that the reaction doesn't happen too quickly.
Physics
2 answers:
horsena [70]3 years ago
5 0

Correct answer is B

Explanation:

Control rods in Nuclear reactor:

During nuclear reaction when a heavy nucleus break up into two light nuclei that time neutron are release and these neutrons further break up other nucleus which release more neutrons which lead to a chain reaction. the nuclear reaction is kept from going critical by keeping the rate of reaction safe by using control rods. Controls rods absorb excess neutrons, keeping them from causing too many uranium atoms to split too quickly.

stepan [7]3 years ago
3 0
I think its B. Sorry if Im wrong.
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Substance A has twice the specific heat capacity as substance B. If 1000 J of heat are added to 1.0 kg of each substance, compar
Mrrafil [7]
Substance A would have a delta T (change in temp) rise 1/2 the rise in substance B.

Q=mc x delta T

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c= specific heat
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Solve for change in temp=. Q/mc

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Putting into real world scenario of using water to heat a building.

Specific heat of water is 1.
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4 0
3 years ago
An object of mass m is traveling on a horizontal surface. There is a coefficient of kinetic friction  between the object and th
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Answer:

8m * (μg/v)^2

Explanation:

k, the spring constant = ?

(k in terms of μ, m, g, and v.)

Frictional force = μmg

Note: lost KE is converted to work done against the friction + PE of the spring

1/2mv2 = μmgx + 1/2kx^2....equation i

Cancel the 1/2 on both sides

mv^2 = μmgx + kx^2

Lets recall that:

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So we can say that:

1/2mv^2 = (μmgx)+ μmgx

1/2mv^2 = 2 (μmgx)

1/4mv^2 = μmgx

Cancel out m on both sides

1/4v^2 = μgx

Make x subject of the formula

x = (1/4v^2) / (μg)...... equation iii

substitute x to equation ii

But first make k in equation ii subject of the formula

1/2kx^2 = μmgx

k = 2μmg/x

Now substitute x

k = 2μmg / ((1/4v^2) / (μg))

k = 2μmg * ((μg) / (1/4v^2))

k = 8m * (μg/v)^2

8m * (μg/v)^2

7 0
3 years ago
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