Boron:atomic number-5,valency-+3,atomic mass- 11amu
Answer is: 18 moles of lead(II)-nitrate.
Balanced chemical reaction:
3Pb(NO₃)₂ + 2AlCl₃ → 2Al(NO₃)₃ + 3PbCl₂.
n(Al(NO₃)₃) = 12 mol.
From chemical reaction: nAl(NO₃)₃) : n(Pb(NO₃)₂) = 2 : 3.
n(Pb(NO₃)₂) = 3 · 12 mol ÷ 2.
n(Pb(NO₃)₂) = 18 mol; amount of substance.
Al(NO₃)₃ is aluminium nitrate.
AlCl₃ is aluminium chloride.
PH of a solution is -ln[H3O+]
so,in case of A pH=3 or,-log[H3O+]=3 or,[H3O+]=10^-3
in case of B pH=6 pr,-log[H3O+]=6 or, [H3O+]=10^-6
so,hydronium ion concentration in solution A /the hydronium ion concentration in solution Z
=10^-3/10^-6
=1000
2)
Ca(OH)2+2 HNO3=Ca(NO3)2+2 H2O
so the answer is 2.
The reaction to form NH3 is : N2 + 3H2-> 2NH3 12,33g NH3 is 12,33/17,03=0,3 =0,724 moles of NH3 moles NH3. So you need 1,5*0,724 = 1,086 moles H2 1,086*2,016 = 2,189 g of H2 is needed ro form 12,33 g NH3
MITOCHONDRIA.
The powerhouse of a cell is Mitochondria, don’t you even forget this.
