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dimaraw [331]
4 years ago
6

Classify each of these reactions.

Chemistry
1 answer:
Snowcat [4.5K]4 years ago
3 0
<h3><u>Answer;</u></h3>

1)Ba(ClO3)2(s)--->BaCl2(s)+3O2(g) - Redox reaction

2)2NaCl(aq)+K2S(aq)--->Na2S(aq)+2KCl(aq)  - None of the above

3)CaO(s)+CO2(g)--->CaCO3(s)  - None of the above

4)KOH(aq)+AgCl(aq)---->KCl(aq)+AgOH(s) -precipitation reaction

5)Ba(OH)2(aq)+2HNO2(aq)--->Ba(NO2)2(aq)+2H2O(l)  - Acid-base neutralization reaction

<h3><u>Explanation;</u></h3>
  • Ba(ClO3)2(s)--->BaCl2(s)+3O2(g)

In this reaction, chlorine is reduced and oxygen is oxidized. Both reduction and oxidation occur in this reaction. Therefore, this is a redox reaction.

  • 2NaCl(aq)+K2S(aq)--->Na2S(aq)+2KCl(aq)

In this reaction, both Na2S and KCl are soluble in water. Therefore the reaction is non of the above. Since it can not be a double displacement reaction in which two compounds react and cations and anions exchange their places to form new compounds.

  • CaO(s)+CO2(g)--->CaCO3(s)

In this reaction CaO and CO2 combine to form calcium carbonate. This is a synthesis reaction, and thus its none of the above choices

  • KOH(aq)+AgCl(aq)---->KCl(aq)+AgOH(s)

In this reaction, the salt KCl is soluble in water and AgOH is insolubel in water. Therefore, this is a precipitation reaction.

  • Ba(OH)2(aq)+2HNO2(aq)--->Ba(NO2)2(aq)+2H2O(l)

In this reaction, nitrous acid acts as an acid and barium hydroxide acts as a base. Therefore, barium hydroxide and nitrous acid react to form salt and water. Therefore, this reaction is acid-base neutralization reaction.

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So, energy just goes into other things. 

Example: you are born. You have carbon dioxide in your body, (or star dust). When you die, your body releases that gas.

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Which of the following statements is a correct explanation of what occurs when a substance is heated
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Answer:

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Explanation:

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4 0
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WHAT IS PH????
andriy [413]

PH INCLUDES ALL OF THE STATEMENT AND IT IS A SCALE WHICH CHECK THE ACIDIC AND BASIC BEHAVIOR OF SUBSTANCE OR SOLUTION

7 0
3 years ago
Explain why air is a good conductor of heat
mars1129 [50]

Answer:

Hope it helps!

Explanation:

Air molecules are too far to disperse heat energy to one another efficiently. Heat is conducted by molecules and atoms that are very closely bonded together and vibrating at high frequency.

3 0
3 years ago
Suppose now that you wanted to determine the density of a small crystal to confirm that it is sulfur. From the literature, you k
ivolga24 [154]

Answer:

Mix 11.73 mL of CHCl₃ and 8.27 mL of CHBr₃

Explanation:

To begin, it seems your question lacks the name of the pure samples that will be mixed to prepare the liquid mixture. The names are not necessary, as the numerical values are there. However, an internet search tells me they are CHCl₃ (d=1.492g/mL) and CHBr₃ (d=2.890 g/mL).

The mixture has a density of 2.07 g/mL, so <u>20 mL of the mixture would weigh</u>:

20 mL * 2.07 g/mL = 41.4 g

Let X be the volume of CHCl₃ and Y the volume of CHBr₃:

X + Y = 20 mL

The mass of CHCl₃ and CHBr₃ combined have to be equal to the mass of the mixture. We can write that equation using the volume of the samples and their density:

X * 1.492 + Y * 2.890 = 41.4 g

So now we have a system of two equations and two unknowns, we use algebra to solve it:

   1. Express Y in terms of X:

X + Y = 20

  • Y = 20 - X

   2. Replace Y in the second equation:

X * 1.492 + Y * 2.890 = 41.4

  • 1.492*X + 2.890*(20-X) = 41.4

   3. Solve for X:

  • 1.492*X + 57.8 - 2.890*X = 41.4
  • 1.398*X = 16.4
  • X = 11.73 mL

   4. Using the now known value of X, solve for Y:

X + Y = 20

  • 11.73 + Y = 20
  • Y = 8.27 mL

So, to prepare the liquid mixture we would mix 8.27 mL of CHBr₃ and 11.73 mL of  CHCl₃.

7 0
4 years ago
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