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beks73 [17]
3 years ago
15

We place 1.32 mol pcl5in a 1.0 l flask and allow it to reach equilibrium at a given temperature. what is the final concentration

of cl2in the flask?
Chemistry
1 answer:
Lady_Fox [76]3 years ago
8 0
I have no idea, sorry
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Calculate the energy required to heat of ethanol from to . Assume the specific heat capacity of ethanol under these conditions i
Marianna [84]

Answer:

17 kJ

Explanation:

Calculation for the Calculate the energy required to heat 0.60kg of ethanol from 2.2°C to 13.7°C.

Using this formula

q = mC∆T

Where,

q represent Energy

m represent Mass of substance=0.60kg=600g

C represent Specific heat capacity=2.44J·g−1K−1.

∆T represent change in Temperature=2.2°C to 13.7°C.

Let plug in the formula

q=(0.60 kg x 1000 g/kg)(2.44 J/gº)(13.7°C-2.2°C)

q = (600g)(2.44 J/gº)(11.5º)

q=16.836 kJ

q= 17 kJ (Approximately)

Therefore the energy required to heat 0.60kg of ethanol from 2.2°C to 13.7°C will be 17 kJ

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3 years ago
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Anestetic [448]

intrusive

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7 0
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An element like silicon is not usually used to make wires or pans because it?
svetlana [45]
It is not good conductors of electricity or heat!
5 0
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What can be categorized as a use of plasma in technology
Pachacha [2.7K]

Plasma technology is based on a simple physical principle. Matter changes its state when energy is supplied to it: solids becomes liquid, and liquids becomes gaseous. If even more energy is supplied to a gas, it is ionized and goes into the energy-rich plasma state, the fourth state of matter.ore than 99% of the visible matter in the universe is in the plasma state.

3 0
3 years ago
Consider this initial-rate data at a certain temperature for the reaction described by N2O3(
Yuliya22 [10]

<span><span>N2</span><span>O3</span><span>(g)</span>→NO<span>(g)</span>+<span>NO2</span><span>(g)</span></span>

<span><span>[<span>N2</span><span>O3</span>]</span> Initial Rate</span>
<span>0.1 M     r<span>(t)</span>=0.66</span> M/s
<span>0.2 M     r<span>(t)</span>=1.32</span> M/s
<span>0.3 M     r<span>(t)</span>=1.98</span> M/s

We can have the relationship:

<span>(<span><span>[<span>N2</span><span>O3</span>]/</span><span><span>[<span>N2</span><span>O3</span>]</span>0</span></span>)^m</span>=<span><span>r<span>(t)/</span></span><span><span>r0</span><span>(t)
However,
</span></span></span>([N2O3]/[N2O3]0) = 2

Also, we assume m=1 which is the order of the reaction.

Thus, the relationship is simplified to,

r(t)/r0(t) = 2

r<span>(t)</span>=k<span>[<span>N2</span><span>O3</span>]</span>

0.66 <span>M/s=k×0.1 M</span>

<span>k=6.6</span> <span>s<span>−<span>1</span></span></span>

6 0
3 years ago
Read 2 more answers
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