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uranmaximum [27]
2 years ago
5

UNA ALEACIÓN DE DOS METALES A Y B TIENE UNA DENSIDAD RELATIVA DE 5 LAS DENSIDADES RELATIVAS DE A Y B RESPECTIVAMENTE SON 4 Y 10

CALCULAR EL PORCENTAJE EN MASA DE A Y EL POCENTAJE EN VOLUMEN DE B
Chemistry
2 answers:
jek_recluse [69]2 years ago
6 0
AN ALLOY OF TWO METALS A AND B HAS A RELATIVE DENSITY OF 5 THE RELATIVE DENSITIES OF A AND B RESPECTIVELY ARE 4 AND 10 CALCULATE THE PERCENTAGE BY MASS OF A AND THE PERCENTAGE BY VOLUME OF B. I don’t know the answer but that’s in English hopefully someone can help that knows the answer
nadezda [96]2 years ago
5 0

Answer:

Explanation:

English please?

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How many moles of oxygen will occupy a volume of 2.50 liters?
loris [4]
Data:
n (number of mols) = ? 
V (volume) = 2.50 Liters 
If: 
1 L → 1000 g
2.50 L → y

y = 1000*2.50 = 2500 g

Therefore:
m (mass) = 2500 g

Now:
Molar Mass (MM) of oxygen = 16 g/mol

Formula:
n =  \frac{m}{MM}

Solving:
n = \frac{m}{MM}
n = \frac{2500\:\diagup\!\!\!\!\!g}{16\:\diagup\!\!\!\!\!g/mol}
\boxed{\boxed{n = 156.25\:mols}}\end{array}}\qquad\quad\checkmark




7 0
3 years ago
A gas has a pressure of 8.5atm and occupies 24L at 25∘C. What volume (in liters) will the gas occupy if the pressure is increase
Vesna [10]

The volume (in liters) that the gas will occupy if the pressure is increased to 13.5 atm and the temperature is decreased to 15 °C is 15 L

From the question given above, the following data were obtained:

Initial pressure (P₁) = 8.5 atm

Initial volume (V₁) = 24 L

Initial temperature (T₁) = 25 °C = 25 + 273 = 298 K

Final pressure (P₂) = 13.5 atm

Final temperature (T₂) = 15 °C = 15 + 273 = 288 K

<h3>Final volume (V₂) =? </h3>

  • The final volume of the gas can be obtained by using the combined gas equation as illustrated below:

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\\\frac{8.5 * 24}{298}  = \frac{13.5 * V_{2}}{288}\\\\ \frac{204}{298} = \frac{13.5 * V_{2}}{288}\\\\

Cross multiply

298 × 13.5 × V₂ = 204 × 288

4023 × V₂ = 58752

Divide both side by 4023

V_{2} = \frac{58752}{4023}\\\\

<h3>V₂ = 15 L </h3>

Therefore, the final volume of the gas is 15 L

Learn more: brainly.com/question/25547148

3 0
2 years ago
2CO + O2 --&gt; 2002
olga_2 [115]
8 moles I think I’m not sure
4 0
3 years ago
What is the volume of an object that has a mass of 3.5 grams and has a density of 2.50 g/mL? Include units and proper sig figs l
jolli1 [7]

1.4mL

Explanation:

Given parameters:

Mass of object = 3.5g

density = 2.5g/mL

Unknown:

Volume of the object = ?

Solution:

Density is the mass per unit volume of a body. It is an intensive property that is the same for the same substances.

   Density = \frac{mass}{volume}

  since the volume is unknown; we make it the subject of the formula;

 Volume = \frac{mass}{density}

Volume = \frac{3.5}{2.5}

Volume of the object = 1.4mL

learn more:

Density brainly.com/question/4825250

#learnwithBrainly

8 0
3 years ago
a 1.00litre vessel contains 0.215 mole of nitrogen gas and 0.0118 mole of hydrogen gas at 25°C. determine the partial pressure o
stepladder [879]

Answer:

THANK YOU SA BRAINLIEST

8 0
2 years ago
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