The volume (in liters) that the gas will occupy if the pressure is increased to 13.5 atm and the temperature is decreased to 15 °C is 15 L
From the question given above, the following data were obtained:
Initial pressure (P₁) = 8.5 atm
Initial volume (V₁) = 24 L
Initial temperature (T₁) = 25 °C = 25 + 273 = 298 K
Final pressure (P₂) = 13.5 atm
Final temperature (T₂) = 15 °C = 15 + 273 = 288 K
<h3>Final volume (V₂) =? </h3>Cross multiply
298 × 13.5 × V₂ = 204 × 288
4023 × V₂ = 58752
Divide both side by 4023
Therefore, the final volume of the gas is 15 L
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1.4mL
Explanation:
Given parameters:
Mass of object = 3.5g
density = 2.5g/mL
Unknown:
Volume of the object = ?
Solution:
Density is the mass per unit volume of a body. It is an intensive property that is the same for the same substances.
Density =
since the volume is unknown; we make it the subject of the formula;
Volume =
Volume =
Volume of the object = 1.4mL
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Density brainly.com/question/4825250
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