All categories

2 years ago

Where is the epicenter of this hypothetical earthquake?

Chemistry

1 answer:

Zolol [24]2 years ago

6 0

Answer:

In fact, the epicenter of a hypothetical earthquake is located at the point where the earthquake begins to break. The epicenter is just above the surface of 'our planet'. The epicenter is what we call immediately above the 'hypocenter' of the earthquake on the stage that said surface.

Explanation:

You might be interested in

sing any data you can find in the ALEKS Data resource, calculate the equilibrium constant K at 25.0°C for the following reaction

prisoha [69]

Answer:

2.76 × 10⁻¹¹

Explanation:

I don’t have access to the ALEKS Data resource, so I used a different source. The number may be different from yours.

1. Calculate the free energy of formation of CCl₄

C(s)+ 2Cl₂(g)→ CCl₄(g)

ΔG°/ mol·L⁻¹: 0 0 -65.3

ΔᵣG° = ΔG°f(products) - ΔG°f(reactants) = -65.3 kJ·mol⁻¹

2. Calculate K

$\text{The relationship between $\Delta G^{\circ}$ and K is}\\\Delta G^{\circ} = -RT \ln K$

T = (25.0 + 273.15) K = 298.15 K

$\begin{array}{rcl}-65 300 & = & -8.314 \times 298.15 \ln K \\65300& = & 2479 \ln K\\26.34 & = & \ln K\\K& = & e^{26.34}\\&= & \mathbf{2.76 \times 10}^{\mathbf{11}}\\\end{array}$

3 0

3 years ago

A chamber with a fixed volume is shown above. The temperature of the gas inside the chamber before heating is 25.2 C and it’s pr

rusak2 [61]

Answer:

Explanation:

Given parameters:

Initial temperature T₁ = 25.2°C = 25.2 + 273 = 298.2K

Initial pressure = P₁ = 0.6atm

Final temperature = 72.4°C = 72.4 + 273 = 345.4K

Unknown:

Final pressure = ?

Solution:

To solve this problem, we use an adaption of the combined gas law where the volume gas is fixed. This simplification results into:

$\frac{P_{1} }{T_{1} } = \frac{P_{2} }{T_{2} }$

where P and T are temperatures, 1 and 2 are initial and final temperatures.

Input the parameters and solve;

$\frac{0.6}{298.2} = \frac{P_{2} }{345.4}$

P₂ = 0.7atm

3 0

3 years ago

1. How would the series of figures change in the presence of a catalyst?

statuscvo [17]

No, it won't change the amount of reactants nor the products as a catalyst will only provide an alternative path where lower activation energy is needed for the process to take place.

hope this explains it

If it does, please give it a brainliest :)))

8 0

3 years ago

Read 2 more answers

Convert the following to grams, <br> a. 0.100 moles of CO2

Svetlanka [38]

.100 mol CO2 x $\frac{44.01 g}{1 mol}$
using the values of the periodic you first add the masses of C (12.01g) and O (there are two so it'll be 32.00g). That value will give the mass of 1mole of CO2.

I hate to do this, but
https://youtu.be/Pft2CASl0M0 is a link to a mr andersen video. I dislike watching these cause this is what my teacher uses instead of actually having to teach herself.

3 0

3 years ago

What science project should i do?

GalinKa [24]

You should do which candle burn the fastest colored or white

6 0

3 years ago

Read 2 more answers