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lora16 [44]
3 years ago
10

An electron (m=9.11x10^-31 kg) moves in a circle whose radius is 2.00x10^-2 m. If the force acting on the electron is 4.60x10^-1

4 N, what is it’s speed?
Physics
1 answer:
harina [27]3 years ago
4 0

Answer:

The speed of the electron is v = 1.01 x 10¹⁵ m/s

Explanation:

Given data,

The mass of the electron, m = 9.11 x 10⁻³¹ kg

The radius of the circle, r = 2.00 x 10⁻² m

The force acting on electron, F = 4.60 x 10⁻¹⁴ N

The speed of the electron, v = ?

The centripetal force of the electron is given by

                                          F = mv² / r

∴                                         v² = Fr/m

                                           v =√(Fr/m)

Substituting the given values in the above equation,

                                          v =√( 4.60 x 10⁻¹⁴ x 2.00 x 10⁻² / 9.11 x 10⁻³¹ )

                                           v = 1.01 x 10¹⁵ m/s

Hence, the speed of the electron is v = 1.01 x 10¹⁵ m/s

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Answer:

The  fraction fraction of the final energy is stored in an initially uncharged capacitor after it has been charging for 3.0 time constants is  

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       V^2 =  0.903  V_o ^2

Hence the fraction of the energy stored in an initially uncharged capacitor is  

      k  = 0.903

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