Question

An electron (m=9.11x10^-31 kg) moves in a circle whose radius is 2.00x10^-2 m. If the force acting on the electron is 4.60x10^-14 N, what is it’s speed?

Answer 1

Answer:

The speed of the electron is v = 1.01 x 10¹⁵ m/s

Explanation:

Given data,

The mass of the electron, m = 9.11 x 10⁻³¹ kg

The radius of the circle, r = 2.00 x 10⁻² m

The force acting on electron, F = 4.60 x 10⁻¹⁴ N

The speed of the electron, v = ?

The centripetal force of the electron is given by

                                          F = mv² / r

∴                                         v² = Fr/m

                                           v =√(Fr/m)

Substituting the given values in the above equation,

                                          v =√( 4.60 x 10⁻¹⁴ x 2.00 x 10⁻² / 9.11 x 10⁻³¹ )

                                           v = 1.01 x 10¹⁵ m/s

Hence, the speed of the electron is v = 1.01 x 10¹⁵ m/s