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lora16 [44]
3 years ago
10

An electron (m=9.11x10^-31 kg) moves in a circle whose radius is 2.00x10^-2 m. If the force acting on the electron is 4.60x10^-1

4 N, what is it’s speed?
Physics
1 answer:
harina [27]3 years ago
4 0

Answer:

The speed of the electron is v = 1.01 x 10¹⁵ m/s

Explanation:

Given data,

The mass of the electron, m = 9.11 x 10⁻³¹ kg

The radius of the circle, r = 2.00 x 10⁻² m

The force acting on electron, F = 4.60 x 10⁻¹⁴ N

The speed of the electron, v = ?

The centripetal force of the electron is given by

                                          F = mv² / r

∴                                         v² = Fr/m

                                           v =√(Fr/m)

Substituting the given values in the above equation,

                                          v =√( 4.60 x 10⁻¹⁴ x 2.00 x 10⁻² / 9.11 x 10⁻³¹ )

                                           v = 1.01 x 10¹⁵ m/s

Hence, the speed of the electron is v = 1.01 x 10¹⁵ m/s

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The total momentum of Elena and Madison is equal to the algebraic sum of their momenta; taking into account the correct signs, we have:

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4. 0.72 m/s to the left

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The initial momentum is the one calculated at the previous step:

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while the final momentum (after the collision) is given by

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m_e is Elena's mass

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According to the law of conservation of momentum,

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v=\frac{p_i}{m_e + m_m}=\frac{-90.5 kg m/s}{60.0 kg+65.0 kg}=-0.72 m/s

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An object ends up at a final position of x=-55.25 meters after a displacement of -189.34 meters after a displacement of -189.34
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The initial position of the object was found to be 134.09 m.

<u>Explanation:</u>

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