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Lady bird [3.3K]
2 years ago
9

. A paper airplane of .025kg is falling at a rate 2m/s2. What is the amount of net force?

Physics
1 answer:
Pie2 years ago
6 0

Answer:

<h2>0.05 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 0.025 × 2

We have the final answer as

<h3>0.05 N</h3>

Hope this helps you

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Estimate how much power is saved if the voltage is stepped up from 150 VV to 1500 VV and then down again, rather than simply tra
gtnhenbr [62]

The question is incomplete! The complete question along with answer and explanation is provided below.

Question:

Suppose 79 kW is to arrive at a town over two 0.115 Ω lines. Estimate how much power is saved if the voltage is stepped up from 150 V to 1500 V and then down again, rather than simply transmitting at 150 V. Assume the transformers are each 99%% efficient. Express your ans up to two decimal points.

Answer:

Power saved = 30772.58 W or 30.77 kW

Explanation:

Since the power loss depends upon current, we need to find the current at each voltage level.

Current at 150 V:

I = P/V = 79,000/150 = 526.67 A

Current at 1500 V:

Considering transformer efficiency of 99%

79,000/0.99 = 79797.97 W

I = P/V = 79,797.97/1500 = 53.19 A

Power loss at 150 V:

P = I²R = (526.67)²*0.115 = 31898.84 W

Power loss at 1500 V:

Here we have to consider both of the losses, due to the transmission line and due to transformer itself

P = I²R = (53.19)²*0.115 = 325.35 W

So the total power at the sending end would be

Receiving end power + losses

79,000 + 325.35 = 79,325 W

Power at the input of the transformer is

79,325/0.99 = 80126.26

Power lost in the transformer is

80,126.26 - 79,000 = 1126.26 W

So the power that can be saved by stepping up the voltage from 150 to 1500 V is

Power saved = 31898.84 - 1126.26

Power saved = 30772.58 W

Power saved = 30.77 kW

3 0
3 years ago
You are climbing in the High Sierra when you suddenly find yourself at the edge of a fog-shrouded cliff. To find the height of t
s344n2d4d5 [400]

Answer:

Height with sound ignored = Gravity x Time taken = 9.8 x 8.60 = 84.28 meters

Time taken by the sound = 84.28/330 = 0.255 seconds

Height with sound involved = (84.28 x 0.255) + 84.28 = 105.80 meters

a. Underestimated

5 0
3 years ago
What happens to the total mass of a substance undergoing a physical change?
Fudgin [204]
I think that your answer would be A. because matter never just goes away in any situation, even if it gets away from you.
4 0
2 years ago
How fast is the runner moving between 2-3 seconds? Is the other question please help
Rainbow [258]

Answer:

Concept: Physics analysis

  1. We have a distance vs time graph
  2. That indicates that we are analyzing the distance traveled by either a person or a particle
  3. The runner starts at 4 meters and over the interval of a second runs to 12 meters reaching the 16 meter mark. The runner stood at 16 meter mark for one full second and then runs back 10 meter over the course of one second reaching 6 meter. The runner runs forward again for a second traveling 6 meters, ending at the 12 meter mark.

4 0
2 years ago
What is the acceleration of a car that moves at a steady velocity of 100 km/h for 100 seconds? Explain your answer.
RUDIKE [14]

Answer:

a = 0 m/s²

Explanation:

given,

car moving at steady velocity = 100 Km/h

         1 km/h = 0.278 m/s

      100 Km/h = 27.8 m/s

time of acceleration = 100 s

acceleration is equal to change in velocity per unit time.

 a=\dfrac{dv}{dt}

change in velocity of the car is 27.8 - 27.8 = 0

 a=\dfrac{0}{100}

        a = 0 m/s²

If the car is moving with steady velocity then acceleration of the car is zero.

Hence, the acceleration of the car is equal to a = 0 m/s²

3 0
3 years ago
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