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adelina 88 [10]
3 years ago
6

A scientist discovers a fossil of an animal and places it in the fossil record. The organism’s bones are similar to the bones of

animal T, which appears earlier in the fossil record. Which conclusion is most reasonable?(1 point)
1. The fossils came from the same organism.

2. The fossils are from an ancestor of animal T.

3. The fossils are from animals that lived at the same time.

4. The fossils are from a descendant of animal T.
Physics
1 answer:
ZanzabumX [31]3 years ago
3 0

Answer:

I think 3

Explanation:

That makes sense

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27N-(u)(14kg)(9.8m/s^2)=0
atroni [7]
If u is about 0.2 (no unit) then the whole left side is zero.
4 0
4 years ago
93 cm3 liquid has a mass of 77 g. When calculating its density what is the appropriate number of significant figures
lubasha [3.4K]

Answer:

828 kg/m³ or 0.828 g/cm³

Explanation:

Applying,

D = m/V............. Equation 1

Where D = density of the liquid, m = mass of the liquid, V = volume of the liquid.

From the question,

Given: m = 77 g , V = 93 cm³

Substitute these values into equation 1

D = 77/93

D = 0.828 g/cm³

Converting to kg/m³

D = 828 kg/m³

6 0
3 years ago
Which of the following statements are true? (There may be more than one correct choice.)
Luba_88 [7]

Answer:

option (A)

Explanation:

According to the Archimede's principle, when a body s immersed partly or wholly in a liquid, it experiences an upward force which is called buoyant force. The buoyant force is equal to the loss in the weight of body.

The weight of liquid displaces by the body is equal to the loss in weight of body.

Thus, option (a) is true.

5 0
4 years ago
9. A wave on Beaver Dam Lake passes by two docks that are 40.0 m apart.
Kobotan [32]

Answers:

a) 10 m

b) time=1.6 s, frquency=0.625 Hz

c) 6.25 m/s

Explanation:

a) If there is a crest at each dock and another three crests between the two docks, and the wavelength \lambda is the distance between to crests; this means we have 4\lambda in 40 m:

40 m=4\lambda

Clearing \lambda:

\lambda=\frac{40 m}{4}

\lambda=10 m

b) This part can be solved by a Rule of Three:

If 10 waves ---- 16 s

1 wave ----- T

Then:

T=\frac{(1 wave)(16 s)}{10 waves}

T=1.6 s This is the period of the wave

On the other hand, the frequency f of the wave has an inverse relation with its period T:

f=\frac{1}{T}

f=\frac{1}{1.6 s}

f=0.625 Hz This is the frequency of the wave

c) The speed v of a wave is given by the following equation:

v=\frac{\lambda}{T}

v=\frac{10 m}{1.6 s}

Finally:

v=6.25 m/s

4 0
3 years ago
For a particular pipe in a pipe-organ, it has been determined that the frequencies 296 Hz and 370 Hz are two adjacent natural fr
user100 [1]

Answer:

fundamental frequency of pipe will be equal to 74 Hz

Explanation:

We have given for a particular organ pipe two adjacent frequency are 296 Hz and 370 Hz

Speed of the sound in air is 343 m/sec

We have to find the fundamental frequency for the pipe

Fundamental frequency will be equal to difference of the two adjacent frequency

So fundamental frequency = 370 - 296 = 74 Hz

So fundamental frequency of pipe will be equal to 74 Hz

8 0
3 years ago
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